如何使用moment.js计算Javascript中两个日期之间的"工作日"数？

Question

如何使用moment.js计算JavaScript中两个日期之间的工作日数.我有一个计算这些天的工作公式,但公式不满足所有条件:

这是我的代码:

var start= moment(data[x].start_date);
                var end= moment(data[x].est_end_date);
                var difference= end.diff(start, 'days');
                var workingDays= Math.round((difference/7)*5);
//data[x] is for iterating over a loop

我在这里每7天得到5天,因为星期六和星期日被视为非工作日,但如果从星期日或星期六开始计算天数,这个公式就会失败.

在这方面,任何人都可以帮助必须做出必要的改变以避免这个问题.

Answer 1

把它分成3个部分..第一周,上周和中间,这样的事情:

function workday_count(start,end) {
  var first = start.clone().endOf('week'); // end of first week
  var last = end.clone().startOf('week'); // start of last week
  var days = last.diff(first,'days') * 5 / 7; // this will always multiply of 7
  var wfirst = first.day() - start.day(); // check first week
  if(start.day() == 0) --wfirst; // -1 if start with sunday 
  var wlast = end.day() - last.day(); // check last week
  if(end.day() == 6) --wlast; // -1 if end with saturday
  return wfirst + days + wlast; // get the total
}

测试代码

var ftest = {date:'2015-02-0',start:1,end:7};
var ltest = {date:'2015-02-2',start:2,end:8};
var f = 'YYYY-MM-DD';
for(var z=ftest.start; z<=ftest.end; ++z) {
  var start = moment(ftest.date + z);
  for(var y=ltest.start; y<=ltest.end; ++y) {
    var end = moment(ltest.date + y);
    var wd = workday_count(start,end);
    console.log('from: '+start.format(f),'to: '+end.format(f),'is '+wd+' workday(s)');
  }
}

输出测试代码:

from: 2015-02-01 to: 2015-02-22 is 15 workday(s)
from: 2015-02-01 to: 2015-02-23 is 16 workday(s)
from: 2015-02-01 to: 2015-02-24 is 17 workday(s)
from: 2015-02-01 to: 2015-02-25 is 18 workday(s)
from: 2015-02-01 to: 2015-02-26 is 19 workday(s)
from: 2015-02-01 to: 2015-02-27 is 20 workday(s)
from: 2015-02-01 to: 2015-02-28 is 20 workday(s)
from: 2015-02-02 to: 2015-02-22 is 15 workday(s)
from: 2015-02-02 to: 2015-02-23 is 16 workday(s)
from: 2015-02-02 to: 2015-02-24 is 17 workday(s)
from: 2015-02-02 to: 2015-02-25 is 18 workday(s)
from: 2015-02-02 to: 2015-02-26 is 19 workday(s)
from: 2015-02-02 to: 2015-02-27 is 20 workday(s)
from: 2015-02-02 to: 2015-02-28 is 20 workday(s)
from: 2015-02-03 to: 2015-02-22 is 14 workday(s)
from: 2015-02-03 to: 2015-02-23 is 15 workday(s)
from: 2015-02-03 to: 2015-02-24 is 16 workday(s)
from: 2015-02-03 to: 2015-02-25 is 17 workday(s)
from: 2015-02-03 to: 2015-02-26 is 18 workday(s)
from: 2015-02-03 to: 2015-02-27 is 19 workday(s)
from: 2015-02-03 to: 2015-02-28 is 19 workday(s)
from: 2015-02-04 to: 2015-02-22 is 13 workday(s)
from: 2015-02-04 to: 2015-02-23 is 14 workday(s)
from: 2015-02-04 to: 2015-02-24 is 15 workday(s)
from: 2015-02-04 to: 2015-02-25 is 16 workday(s)
from: 2015-02-04 to: 2015-02-26 is 17 workday(s)
from: 2015-02-04 to: 2015-02-27 is 18 workday(s)
from: 2015-02-04 to: 2015-02-28 is 18 workday(s)
from: 2015-02-05 to: 2015-02-22 is 12 workday(s)
from: 2015-02-05 to: 2015-02-23 is 13 workday(s)
from: 2015-02-05 to: 2015-02-24 is 14 workday(s)
from: 2015-02-05 to: 2015-02-25 is 15 workday(s)
from: 2015-02-05 to: 2015-02-26 is 16 workday(s)
from: 2015-02-05 to: 2015-02-27 is 17 workday(s)
from: 2015-02-05 to: 2015-02-28 is 17 workday(s)
from: 2015-02-06 to: 2015-02-22 is 11 workday(s)
from: 2015-02-06 to: 2015-02-23 is 12 workday(s)
from: 2015-02-06 to: 2015-02-24 is 13 workday(s)
from: 2015-02-06 to: 2015-02-25 is 14 workday(s)
from: 2015-02-06 to: 2015-02-26 is 15 workday(s)
from: 2015-02-06 to: 2015-02-27 is 16 workday(s)
from: 2015-02-06 to: 2015-02-28 is 16 workday(s)
from: 2015-02-07 to: 2015-02-22 is 10 workday(s)
from: 2015-02-07 to: 2015-02-23 is 11 workday(s)
from: 2015-02-07 to: 2015-02-24 is 12 workday(s)
from: 2015-02-07 to: 2015-02-25 is 13 workday(s)
from: 2015-02-07 to: 2015-02-26 is 14 workday(s)
from: 2015-02-07 to: 2015-02-27 is 15 workday(s)
from: 2015-02-07 to: 2015-02-28 is 15 workday(s)

Answer 2

我发现如果日子在同一周内（例如从太阳到星期六），kokizzu 的答案不起作用，所以解决了这个问题：

    function calcBusinessDays(startDate, endDate) { 
      var day = moment(startDate);
      var businessDays = 0;

      while (day.isSameOrBefore(endDate,'day')) {
        if (day.day()!=0 && day.day()!=6) businessDays++;
        day.add(1,'d');
      }
      return businessDays;
    }

Answer 3

我已经对 Kokizzu 的答案进行了改编，以解决夏令时问题。在巴西时区 (GMT -3) 中，17/10/2017 和 18/10/2017 之间的差异为 -2.71，而不是 2。

本周的开始时间为 15/10/2017 00:00 UTC 或 14/10/2017 21:00-03:00

本周末为 22/10/2017 00:00 UTC 或 21/10/2017 22:00-02:00（夏令时）

因此，“第一个”和“最后一个”变量之间的天数差异不是 7，而是 6（或 8，具体取决于您的时区）。

修复后的代码如下：

start = moment(start).utc().add(start.utcOffset(), 'm'); // Ignore timezones
end = moment(end).utc().add(end.utcOffset(), 'm'); // Ignore timezones

var first = start.clone().endOf('week'); // end of first week
var last = end.clone().startOf('week'); // start of last week

// Fixing Summer Time problems
firstCorrection = moment(first).utc().add(60, 'm').toDate(); //
var days = last.diff(firstCorrection,'days') * 5 / 7; // this will always multiply of 7

var wfirst = first.day() - start.day(); // check first week
if(start.day() == 0) --wfirst; // -1 if start with sunday
var wlast = end.day() - last.day(); // check last week
if(end.day() == 6) --wlast; // -1 if end with saturday
return wfirst + days + wlast; // get the total (subtract holidays if needed)

Answer 4

我使用一个简单的函数来完成该任务。也许不是最有效的，但可以。它不需要Moment.js。这只是Javascript。

function getNumWorkDays(startDate, endDate) {
    var numWorkDays = 0;
    var currentDate = new Date(startDate);
    while (currentDate <= endDate) {
        // Skips Sunday and Saturday
        if (currentDate.getDay() !== 0 && currentDate.getDay() !== 6) {
            numWorkDays++;
        }
        currentDate = currentDate.addDays(1);
    }
    return numWorkDays;
}

到addDays，我使用以下功能：

Date.prototype.addDays = function (days) {
    var date = new Date(this.valueOf());
    date.setDate(date.getDate() + days);
    return date;
};