Hag*_*ble 6 c malloc pointers multidimensional-array
昨天我发布了一个问题:我应该如何传递指向函数的指针并为被调用函数内部传递的指针分配内存?
从我得到的答案中,我能够理解我在做什么错误.
我现在面临一个新问题,任何人都可以帮忙解决这个问题吗?
我想动态分配一个2D数组,所以我将一个Pointer-to-Pointer从my main()传递给另一个调用的函数alloc_2D_pixels(...),在那里我使用malloc(...)并for(...)循环为2D数组分配内存.
好吧,从alloc_2D_pixels(...)函数返回后,指针指针仍然保持为NULL,所以很自然地,当我尝试访问或尝试free(...)指针到指针时,程序挂起.
谁能告诉我我在这里犯的错误?
救命!!!
维克拉姆
资源:
main()
{
unsigned char **ptr;
unsigned int rows, cols;
if(alloc_2D_pixels(&ptr, rows, cols)==ERROR) // Satisfies this condition
printf("Memory for the 2D array not allocated"); // NO ERROR is returned
if(ptr == NULL) // ptr is NULL so no memory was allocated
printf("Yes its NULL!");
// Because ptr is NULL, with any of these 3 statements below the program HANGS
ptr[0][0] = 10;
printf("Element: %d",ptr[0][0]);
free_2D_alloc(&ptr);
}
signed char alloc_2D_pixels(unsigned char ***memory, unsigned int rows, unsigned int cols)
{
signed char status = NO_ERROR;
memory = malloc(rows * sizeof(unsigned char** ));
if(memory == NULL)
{
status = ERROR;
printf("ERROR: Memory allocation failed!");
}
else
{
int i;
for(i = 0; i< cols; i++)
{
memory[i] = malloc(cols * sizeof(unsigned char));
if(memory[i]==NULL)
{
status = ERROR;
printf("ERROR: Memory allocation failed!");
}
}
}
// Inserted the statements below for debug purpose only
memory[0][0] = (unsigned char)10; // I'm able to access the array from
printf("\nElement %d",memory[0][0]); // here with no problems
return status;
}
void free_2D_pixels(unsigned char ***ptr, unsigned int rows)
{
int i;
for(i = 0; i < rows; i++)
{
free(ptr[i]);
}
free(ptr);
}
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一个错误是发布无法编译的代码:)。下面是更正后的代码,其中包含我在
/* 这种样式 */ 中的注释:
/* Next four lines get your code to compile */
#include <stdio.h>
#include <stdlib.h>
#define NO_ERROR 0
#define ERROR 1
/* prototypes for functions used by main but declared after main
(or move main to the end of the file */
signed char alloc_2D_pixels(unsigned char*** memory, unsigned int rows, unsigned int cols);
void free_2D_pixels(unsigned char** ptr, unsigned int rows);
/* main should return int */
int main()
{
unsigned char** ptr;
/* need to define rows and cols with an actual value */
unsigned int rows = 5, cols = 5;
if(alloc_2D_pixels(&ptr, rows, cols) == ERROR) // Satisfies this condition
printf("Memory for the 2D array not allocated"); // ERROR is returned
if(ptr == NULL) // ptr is NULL so no memory was allocated
printf("Yes its NULL!");
else
{
/* Added else clause so below code only runs if allocation worked. */
/* Added code to write to every element as a test. */
unsigned int row,col;
for(row = 0; row < rows; row++)
for(col = 0; col < cols; col++)
ptr[0][0] = (unsigned char)(row + col);
/* no need for &ptr here, not returning anything so no need to pass
by reference */
free_2D_pixels(ptr, rows);
}
return 0;
}
signed char alloc_2D_pixels(unsigned char*** memory, unsigned int rows, unsigned int cols)
{
signed char status = NO_ERROR;
/* In case we fail the returned memory ptr will be initialized */
*memory = NULL;
/* defining a temp ptr, otherwise would have to use (*memory) everywhere
ptr is used (yuck) */
unsigned char** ptr;
/* Each row should only contain an unsigned char*, not an unsigned
char**, because each row will be an array of unsigned char */
ptr = malloc(rows * sizeof(unsigned char*));
if(ptr == NULL)
{
status = ERROR;
printf("ERROR: Memory allocation failed!");
}
else
{
/* rows/cols are unsigned, so this should be too */
unsigned int i;
/* had an error here. alloced rows above so iterate through rows
not cols here */
for(i = 0; i < rows; i++)
{
ptr[i] = malloc(cols * sizeof(unsigned char));
if(ptr[i] == NULL)
{
status = ERROR;
printf("ERROR: Memory allocation failed!");
/* still a problem here, if exiting with error,
should free any column mallocs that were
successful. */
}
}
}
/* it worked so return ptr */
*memory = ptr;
return status;
}
/* no need for *** here. Not modifying and returning ptr */
/* it also was a bug...would've needed (*ptr) everywhere below */
void free_2D_pixels(unsigned char** ptr, unsigned int rows)
{
/* should be unsigned like rows */
unsigned int i;
for(i = 0; i < rows; i++)
{
free(ptr[i]);
}
free(ptr);
}
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