Jes*_*lan 2 java database android image
我正在尝试从我的数据库在线获取图片,在我的"imagelink"中,这是我表中的数据字段,我把那些我上传的图片的网址放在那里,但不幸的是它给了我这个错误.
02-08 15:05:29.432 14364-14364/com.example.jithea.testlogin E/BitmapFactory? Unable to decode stream: java.io.FileNotFoundException: /http:/agustiniancampusevents.site40.net/newsDB/images/Visual%20Report%20Filipino%20Final-12%20copy.JPG: open failed: ENOENT (No such file or directory)
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这是我在onPostExecute中的代码:
protected void onPostExecute(String file_url) {
// dismiss the dialog after getting all products
pDialog.dismiss();
// updating UI from Background Thread
runOnUiThread(new Runnable() {
public void run() {
/**
* Updating parsed JSON data into ListView
* */
ListAdapter adapter = new SimpleAdapter(
NewsActivity.this, productsList,
R.layout.news_list_item, new String[]{TAG_PID, TAG_IMAGELINK,
TAG_NEWSTITLE, TAG_DESCRIPTION},
new int[]{R.id.pid, R.id.imageView, R.id.newstitle, R.id.description});
// updating listview
setListAdapter(adapter);
}
});
}
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小智 13
用BitmapFactory.decodeStream而不是BitmapFactory.decodeFile.
try ( InputStream is = new URL( file_url ).openStream() ) {
Bitmap bitmap = BitmapFactory.decodeStream( is );
}
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