在mysql中,如何检查两个日期范围是否重叠?
我有这个:
注意:我们有,p.date_started <= p.date_finished
但dateA
可以等于dateB
或小于dateB
或大于dateB
.
码:
$query = "SELECT u.first_name, u.last_name, u.avatar_filename, p.id, p.user_id, p.address, p.topic, p.latitude, p.longitude, d.name AS department_name
FROM user u
JOIN placement p ON p.user_id=u.id
JOIN department d ON d.id = u.department_id
WHERE p.active=1 AND (('{$dateA}' BETWEEN p.date_started AND p.date_finished) OR
('{$dateB}' BETWEEN p.date_started AND p.date_finished) OR
(p.date_started BETWEEN '{$dateA}' AND '{$dateB}') OR
(p.date_finished BETWEEN '{$dateA}' AND '{$dateB}'))";
Run Code Online (Sandbox Code Playgroud)
有没有更好的方法呢?
谢谢
如果我们保证date_started
,datefinished
,$DateA
和$DateB
不为NULL,并且我们保证date_started
不大于date_finished
...
`s` represents `date_started`
`f` represents `date_finished`
`a` represents the smaller of `$DateA` and `$DateB`
`b` represents the larger of `$DateA` and `$DateB`
Run Code Online (Sandbox Code Playgroud)
视觉:
s-----f overlap
-----+-----+----- -------
a-b | | NO
a---b | YES
a-----b | YES
a---------b YES
a-----------b YES
a---b | YES
a-----b YES
a-------b YES
| a-b | YES
| a---b YES
| a-----b YES
| a-b YES
| | a-b NO
Run Code Online (Sandbox Code Playgroud)
我们可以很容易地检测到范围没有"重叠"的时间:
( a > f OR b < s )
Run Code Online (Sandbox Code Playgroud)
我们可以轻易地否定,要返回"真"时,有是一个"重叠":
NOT ( a > f OR b < s )
Run Code Online (Sandbox Code Playgroud)
将其转换为SQL:
NOT ( GREATEST('{$dateA}','{$dateB}') < p.date_started
OR LEAST('{$dateA}','{$dateB}') > p.date_finished
)
Run Code Online (Sandbox Code Playgroud)