mye*_*eu2 4 python list duplicates
这是一个包含重复项的列表:
l1 = ['a', 'b', 'c', 'a', 'a', 'b']
这是期望的结果:
l1 = ['a', 'b', 'c', 'a_1', 'a_2', 'b_1']
如何通过附加计数来重命名重复项?
以下是实现这一目标的尝试; 然而,有更多的Pythonic方式吗?
for index in range(len(l1)):
counter = 1
list_of_duplicates_for_item = [dup_index for dup_index, item in enumerate(l1) if item == l1[index] and l1.count(l1[index]) > 1]
for dup_index in list_of_duplicates_for_item[1:]:
l1[dup_index] = l1[dup_index] + '_' + str(counter)
counter = counter + 1
Run Code Online (Sandbox Code Playgroud)
Joc*_*zel 17
在Python中,生成新列表通常比更改现有列表容易得多.我们有发电机有效地完成这项工作.字典可以保持发生次数.
l = ['a', 'b', 'c', 'a', 'a', 'b']
def rename_duplicates( old ):
seen = {}
for x in old:
if x in seen:
seen[x] += 1
yield "%s_%d" % (x, seen[x])
else:
seen[x] = 0
yield x
print list(rename_duplicates(l))
Run Code Online (Sandbox Code Playgroud)
小智 5
我会做这样的事情:
a1 = ['a', 'b', 'c', 'a', 'a', 'b']
a2 = []
d = {}
for i in a1:
d.setdefault(i, -1)
d[i] += 1
if d[i] >= 1:
a2.append('%s_%d' % (i, d[i]))
else:
a2.append(i)
print a2
Run Code Online (Sandbox Code Playgroud)
归档时间: |
|
查看次数: |
1578 次 |
最近记录: |