RGR*_*RGR 19 java rest spring multipartform-data resttemplate
我正在尝试上传的文件将始终是一个xml文件.我想将content-type设置为application/xml这是我的代码:
MultiValueMap<String, Object parts = new LinkedMultiValueMap<String,
Object(); parts.add("subject", "some info");
ByteArrayResource xmlFile = new ByteArrayResource(stringWithXMLcontent.getBytes("UTF-8")){
@Override
public String getFilename(){
return documentName;
}
};
parts.add("attachment", xmlFile);
//sending the request using RestTemplate template;, the request is successfull
String result = template.postForObject(getRestURI(), httpEntity,String.class);
//but the content-type of file is 'application/octet-stream'
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原始请求如下所示:
Content-Type:
multipart/form-data;boundary=gbTw7ZJbcdbHIeCRqdX81DVTFfA-oteHHEqgmlz
User-Agent: Java/1.7.0_67 Host: some.host Connection: keep-alive
Content-Length: 202866
--gbTw7ZJbcdbHIeCRqdX81DVTFfA-oteHHEqgmlz Content-Disposition: form-data; name="subject" Content-Type: text/plain;charset=ISO-8859-1
Content-Length: 19
some info
--gbTw7ZJbcdbHIeCRqdX81DVTFfA-oteHHEqgmlz Content-Disposition: form-data; name="attachment"; filename="filename.xml" Content-Type:
application/octet-stream Content-Length: 201402
....xml file contents here ..
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文件的内容类型生成为'application/octet-stream',我希望它是'application/xml'我如何设置文件的内容类型?
RGR*_*RGR 33
我从这个链接中获取提示后想出了解决方案:
使用带有spring for android的压缩jpeg字节数组进行多部分发布请求
解决方法是将ByteArrayResource放在带有必需头的HttpEntity中,并将HttpEntity添加到Multivaluemap(而不是添加ByteArrayResource本身.)
码:
Resource xmlFile = new ByteArrayResource(stringWithXMLcontent.getBytes("UTF-8")){
@Override
public String getFilename(){
return documentName;
}
};
HttpHeaders xmlHeaders = new HttpHeaders();
xmlHeaders.setContentType(MediaType.APPLICATION_XML);
HttpEntity<Resource> xmlEntity = new HttpEntity<Resource>(xmlFile, xmlHeaders);
parts.add("attachment", xmlEntity);
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