如何在使用RestTemplate(来自其他客户端)时为分段上传中的文件设置内容类型

RGR*_*RGR 19 java rest spring multipartform-data resttemplate

我正在尝试上传的文件将始终是一个xml文件.我想将content-type设置为application/xml这是我的代码:

         MultiValueMap<String, Object parts = new LinkedMultiValueMap<String,
         Object(); parts.add("subject", "some info"); 
         ByteArrayResource xmlFile = new    ByteArrayResource(stringWithXMLcontent.getBytes("UTF-8")){
                 @Override
                 public String getFilename(){
                     return documentName;
                 }             
             };

     parts.add("attachment", xmlFile);

//sending the request using RestTemplate template;, the request is successfull 
String result = template.postForObject(getRestURI(), httpEntity,String.class);      
//but the content-type of file is 'application/octet-stream'
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原始请求如下所示:

    Content-Type:
    multipart/form-data;boundary=gbTw7ZJbcdbHIeCRqdX81DVTFfA-oteHHEqgmlz
    User-Agent: Java/1.7.0_67 Host: some.host Connection: keep-alive
    Content-Length: 202866

    --gbTw7ZJbcdbHIeCRqdX81DVTFfA-oteHHEqgmlz Content-Disposition: form-data;    name="subject" Content-Type: text/plain;charset=ISO-8859-1
    Content-Length: 19

    some info

    --gbTw7ZJbcdbHIeCRqdX81DVTFfA-oteHHEqgmlz Content-Disposition: form-data;   name="attachment"; filename="filename.xml" Content-Type:
    application/octet-stream Content-Length: 201402

    ....xml file contents here ..
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文件的内容类型生成为'application/octet-stream',我希望它是'application/xml'我如何设置文件的内容类型?

RGR*_*RGR 33

我从这个链接中获取提示后想出了解决方案:

使用带有spring for android的压缩jpeg字节数组进行多部分发布请求

解决方法是将ByteArrayResource放在带有必需头的HttpEntity中,并将HttpEntity添加到Multivaluemap(而不是添加ByteArrayResource本身.)

码:

Resource xmlFile = new ByteArrayResource(stringWithXMLcontent.getBytes("UTF-8")){
            @Override
            public String getFilename(){
                return documentName;
            }
        };
        HttpHeaders xmlHeaders = new HttpHeaders();
        xmlHeaders.setContentType(MediaType.APPLICATION_XML);
        HttpEntity<Resource> xmlEntity = new HttpEntity<Resource>(xmlFile, xmlHeaders);
        parts.add("attachment", xmlEntity);
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