Slo*_*rry 1 javascript dom reactjs
我不熟悉反应,我尝试在登录/表格等方面构建以下抽象.
看看这个:
var SignUpForm = React.createClass({
handleSubmit: function(e) {
e.preventDefault();
console.log(this.refs.iitu_id.getDOMNode().value.trim())
// iitu_id = this.refs.iitu_id.getDOMNode().value.trim();
// password = this.refs.password.getDOMNode().value.trim();
var error = UserValidator.valid({iitu_id: iitu_id, password: password});
if (error) {
this.setState({"errors": error });
// console.log(error);
} else {
// console.log(error);
}
},
getInitialState: function() {
return {
'errors': {
iitu_id: null,
password: null
}
};
},
render: function() {
return (
/*jshint ignore:start */
<form className="form-horizontal" onSubmit={this.handleSubmit} >
<FormGroup label="iitu id" error_msg={this.state.errors.iitu_id} fieldName="iitu_id" fieldType="text" />
<FormGroup label="password" error_msg={this.state.errors.password} fieldName="password" fieldType="password" />
<ButtonGroup text="?????"/>
</form>
/*jshint ignore:end */
);
}
});
var FormGroup = React.createClass({
render: function() {
var formGroupCss = 'form-group';
if (this.props.error_msg){
formGroupCss = 'form-group has-error';
}
return (
/*jshint ignore:start */
<div className={formGroupCss}>
<Label fieldName={this.props.fieldName}>{this.props.label}</Label>
<InputField type={this.props.fieldType}>{this.props.label}</InputField>
<label className="control-label" for="inputError1">{this.props.error_msg}</label>
</div>
/*jshint ignore:end */
);
}
});
var ButtonGroup = React.createClass({
render: function () {
return (
/*jshint ignore:start */
<div className="form-group">
<div className="col-sm-offset-2 col-sm-10">
<button className="btn btn-default">{this.props.text}</button>
</div>
</div>
/*jshint ignore:end */
);
}
});
var InputField = React.createClass({
render: function() {
return (
/*jshint ignore:start */
<div className="col-sm-5">
<input className="form-control" type={this.props.fieldType} placeholder={this.props.children}/>
</div>
/*jshint ignore:end */
);
}
});
exports.SignUpForm = SignUpForm;
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有太多的代码,但我认为这很容易阅读.问题是当我按下提交按钮时(如果获取表单值),如何获取InputField类的值?我的输入标签存在于DOM内部的问题.另外一个问题是,拥有以下代码设计是否合适?我的意思是将每个逻辑组件描述为新的"类"?
如果您提供表单输入name属性,则可以使用表单的.elements集合来访问其输入.
我最近将newforms用于此的代码拆分为可重用的get-form-data模块,假设您的输入具有name属性,这将允许您执行此操作:
var getFormData = require('get-form-data'); // Or just use the browser bundle
var SignUpForm = React.createClass({
handleSubmit: function(e) {
e.preventDefault();
var data = getFormData(e.target, {trim: true});
var error = UserValidator.valid(data);
if (error) {
this.setState({errors: error});
} else {
// ...
}
},
// ...
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或者,如果您需要获取输入,则可以向包含所有表单输入的其他组件添加onChange处理程序<form>,而不必单独执行每个输入:
handleChange: function(e) {
var form = e.target.form;
var name = e.target.name;
var data = getFormData.getNamedFormElementData(form, name, {trim: true});
// ...
},
render: function() {
return <form onSubmit={this.handleSubmit} onChange={this.handleChange}>
{/* ... */}
</form>
}
});
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