在GridView中过滤相关模型的设置

Question

我试图在Yii2的GridView小部件中为相关模型设置过滤器,但我不断得到错误,因为过滤器值必须是整数.

我跟着这个问题.现在,我有两个型号Services.php和ServiceCharge.php.

在ServiceCharge.php关系设置如下:

public function getServiceName()
    {
        return $this->hasOne(Services::className(),['id'=>'service_name']);
    }

在ServiceChargeSearch.php代码中是这样的:

<?php

namespace app\models;

use Yii;
use yii\base\Model;
use yii\data\ActiveDataProvider;
use app\models\ServiceCharges;

/**
 * ServiceChargesSearch represents the model behind the search form about `app\models\ServiceCharges`.
 */
class ServiceChargesSearch extends ServiceCharges
{
    /**
     * @inheritdoc
     */
    public function attributes()
    {
        // add related fields to searchable attributes
      return array_merge(parent::attributes(), ['serviceName.services']);

    }
    public function rules()
    {
        return [
            [['id'], 'integer'],
            [['charges_cash', 'charges_cashless'], 'number'],
            [['id', 'serviceName.services', 'room_category'], 'safe'],
        ];
    }

    /**
     * @inheritdoc
     */
    public function scenarios()
    {
        // bypass scenarios() implementation in the parent class
        return Model::scenarios();
    }

    /**
     * Creates data provider instance with search query applied
     *
     * @param array $params
     *
     * @return ActiveDataProvider
     */
    public function search($params)
    {
        $query = ServiceCharges::find();

        $dataProvider = new ActiveDataProvider([
            'query' => $query,
        ]);
        $dataProvider->sort->attributes['serviceName.services'] = [
        'asc' => ['serviceName.services' => SORT_ASC],
        'desc' => ['serviceName.services' => SORT_DESC],
        ];

$query->joinWith(['serviceName']); 

        $this->load($params);

        if (!$this->validate()) {
            // uncomment the following line if you do not want to any records when validation fails
            // $query->where('0=1');
            return $dataProvider;
        }

        $query->andFilterWhere([
            'id' => $this->id,
           // 'service_name' => $this->service_name,
            'room_category' => $this->room_category,
            'charges_cash' => $this->charges_cash,
            'charges_cashless' => $this->charges_cashless,
        ])
      ->andFilterWhere(['LIKE', 'serviceName.services', $this->getAttribute('serviceName.services')]);

        return $dataProvider;
    }
}

在我的Gridview中,它设置如下:

[
                'attribute'=>'service_name',
                'value'=>'serviceName.services',

            ],

这是正确显示相关模型的服务名称.

我无法看到我做错了什么,但服务属性的过滤器字段根本没有显示.

Answer 1

实际上它比看起来简单得多.

1. 添加column_name到安全属性.注意:这应该是名称关系

2. 添加查询连接 - 如 - $query->joinWith(['serviceName','roomCategory']);

3. 添加过滤条件如:

   ->andFilterWhere(['like', 'services.services', $this->service_name])
   ->andFilterWhere(['like', 'room_category.room_category', $this->room_category]);
   

4. 如果要添加排序添加代码如:

   $dataProvider->sort->attributes['service_name'] = [
       'asc'  => ['services.services' => SORT_ASC],
       'desc' => ['services.services' => SORT_DESC],
   ];
   $dataProvider->sort->attributes['room_category'] = [
       'asc'  => ['room_category.room_category' => SORT_ASC],
       'desc' => ['room_category.room_category' => SORT_DESC],
   ];
   

5你还应该设置关系名称 public $roomCategory

而已.相关表的排序和过滤都很有效.

注意:删除默认验证,如相关列的整数和默认过滤,gii否则会产生错误.

最新版本更新:

• 不需要添加Public $属性.
• 也不需要为关系添加安全属性.
• 但是当前模型中要将过滤器的属性添加到必须的安全属性中.
• 最重要的是在gridview中,相关属性必须采用闭包格式.

就是这个例子

[
'attribute=>'attribute_name',
'value=function($data){
     return $data->relationname->related_table_attribute_name
}
],

记住你使用relation_name.related_table_attribute_name过滤器不知何故对我不起作用.