Java - 除以零时无法捕获ArithmeticException

Question

我一定在这里做了些蠢事.但我似乎无法弄清楚为什么这个简单的代码不起作用.InputMismatchException有效,但ArithmeticException永远不会被捕获.

import java.util.InputMismatchException;
import java.util.Scanner;
public class SubChap02_DivisionByZero {
    public static double quotient(double num, double denum) throws ArithmeticException {
        return num / denum;
    }

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        double num, denum, result;
        boolean continueLoop = true;
        do {
            try {
                System.out.printf("Please enter the numerator: ");
                num = scanner.nextFloat();
                System.out.printf("Please enter the denumerator: ");
                denum = scanner.nextFloat();
                result = quotient(num, denum);
                continueLoop = false;
                System.out.printf("THIS: %.2f/%.2f is %.2f\n", num, denum, result);    
                scanner.close();
          } catch (ArithmeticException arithmeticException) {
              System.err.printf("Exception : %s\n", arithmeticException);
              scanner.nextLine();
              System.out.println("You can try again!");
          } catch (InputMismatchException inputMismatchException) {
              System.err.printf("Exception : %s\n", inputMismatchException);
              scanner.nextLine();
              System.out.println("You can try again!");
          }
      } while (continueLoop == true);
    }
}

Answer 1

如果你期望ArithmeticException在除以0.0时抛出,它就不会.双由0的Double.POSITIVE_INFINITY除法返回(将正双精度Double.NEGATIVE_INFINITY除以0.0),(将负双精度Double.NaN除以0.0 )或(将0.0除以0.0).

将int除以0将给出此异常.