如何用PHP获取基本URL？

Question

我在Windows Vista上使用XAMPP.在我的发展中,我有http://127.0.0.1/test_website/.

我如何http://127.0.0.1/test_website/使用PHP？

我试过这样的东西,但没有一个有用.

echo dirname(__FILE__)
or
echo basename(__FILE__);
etc.

Answer 1

试试这个:

<?php echo "http://" . $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI']; ?>

了解有关预定义变量的更多信息$_SERVER

如果您打算使用https,可以使用:

function url(){
  return sprintf(
    "%s://%s%s",
    isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] != 'off' ? 'https' : 'http',
    $_SERVER['SERVER_NAME'],
    $_SERVER['REQUEST_URI']
  );
}

echo url();
#=> http://127.0.0.1/foo

根据这个答案,请确保正确配置您的Apache,以便您可以安全地依赖SERVER_NAME.

<VirtualHost *>
    ServerName example.com
    UseCanonicalName on
</VirtualHost>

注意:如果您依赖于HTTP_HOST键(包含用户输入),您仍然需要进行一些清理,删除空格,逗号,回车,任何不是域的有效字符.例如,检查php builtin parse_url函数.

Answer 2

功能调整为执行时没有警告:

function url(){
    if(isset($_SERVER['HTTPS'])){
        $protocol = ($_SERVER['HTTPS'] && $_SERVER['HTTPS'] != "off") ? "https" : "http";
    }
    else{
        $protocol = 'http';
    }
    return $protocol . "://" . $_SERVER['HTTP_HOST'] . $_SERVER['REQUEST_URI'];
}

Answer 3

有趣的'base_url'片段!

if (!function_exists('base_url')) {
    function base_url($atRoot=FALSE, $atCore=FALSE, $parse=FALSE){
        if (isset($_SERVER['HTTP_HOST'])) {
            $http = isset($_SERVER['HTTPS']) && strtolower($_SERVER['HTTPS']) !== 'off' ? 'https' : 'http';
            $hostname = $_SERVER['HTTP_HOST'];
            $dir =  str_replace(basename($_SERVER['SCRIPT_NAME']), '', $_SERVER['SCRIPT_NAME']);

            $core = preg_split('@/@', str_replace($_SERVER['DOCUMENT_ROOT'], '', realpath(dirname(__FILE__))), NULL, PREG_SPLIT_NO_EMPTY);
            $core = $core[0];

            $tmplt = $atRoot ? ($atCore ? "%s://%s/%s/" : "%s://%s/") : ($atCore ? "%s://%s/%s/" : "%s://%s%s");
            $end = $atRoot ? ($atCore ? $core : $hostname) : ($atCore ? $core : $dir);
            $base_url = sprintf( $tmplt, $http, $hostname, $end );
        }
        else $base_url = 'http://localhost/';

        if ($parse) {
            $base_url = parse_url($base_url);
            if (isset($base_url['path'])) if ($base_url['path'] == '/') $base_url['path'] = '';
        }

        return $base_url;
    }
}

使用简单如下:

//  url like: http://stackoverflow.com/questions/2820723/how-to-get-base-url-with-php

echo base_url();    //  will produce something like: http://stackoverflow.com/questions/2820723/
echo base_url(TRUE);    //  will produce something like: http://stackoverflow.com/
echo base_url(TRUE, TRUE); || echo base_url(NULL, TRUE);    //  will produce something like: http://stackoverflow.com/questions/
//  and finally
echo base_url(NULL, NULL, TRUE);
//  will produce something like: 
//      array(3) {
//          ["scheme"]=>
//          string(4) "http"
//          ["host"]=>
//          string(12) "stackoverflow.com"
//          ["path"]=>
//          string(35) "/questions/2820723/"
//      }

Answer 4

   $base_url="http://".$_SERVER['SERVER_NAME'].dirname($_SERVER["REQUEST_URI"].'?').'/';

用法:

print "<script src='{$base_url}js/jquery.min.js'/>";

Answer 5

$modifyUrl = parse_url($url);
print_r($modifyUrl)

它只是简单易用
输出:

Array
(
    [scheme] => http
    [host] => aaa.bbb.com
    [path] => /
)

Answer 6

我认为$_SERVER超全球拥有您正在寻找的信息.它可能是这样的:

echo $_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI']

您可以在此处查看相关的PHP文档.

Answer 7

简单又容易的技巧：

$host  = $_SERVER['HTTP_HOST'];
$host_upper = strtoupper($host);
$path   = rtrim(dirname($_SERVER['PHP_SELF']), '/\\');
$baseurl = "http://" . $host . $path . "/";

网址如下所示：http://example.com/folder/

Answer 8

你可以这样做，但抱歉我的英语不够好。

首先，使用这个简单的代码获取主页 url。

我已经在本地服务器和公共服务器上测试了这段代码，结果很好。

<?php

function home_base_url(){   

// first get http protocol if http or https

$base_url = (isset($_SERVER['HTTPS']) &&

$_SERVER['HTTPS']!='off') ? 'https://' : 'http://';

// get default website root directory

$tmpURL = dirname(__FILE__);

// when use dirname(__FILE__) will return value like this "C:\xampp\htdocs\my_website",

//convert value to http url use string replace, 

// replace any backslashes to slash in this case use chr value "92"

$tmpURL = str_replace(chr(92),'/',$tmpURL);

// now replace any same string in $tmpURL value to null or ''

// and will return value like /localhost/my_website/ or just /my_website/

$tmpURL = str_replace($_SERVER['DOCUMENT_ROOT'],'',$tmpURL);

// delete any slash character in first and last of value

$tmpURL = ltrim($tmpURL,'/');

$tmpURL = rtrim($tmpURL, '/');


// check again if we find any slash string in value then we can assume its local machine

    if (strpos($tmpURL,'/')){

// explode that value and take only first value

       $tmpURL = explode('/',$tmpURL);

       $tmpURL = $tmpURL[0];

      }

// now last steps

// assign protocol in first value

   if ($tmpURL !== $_SERVER['HTTP_HOST'])

// if protocol its http then like this

      $base_url .= $_SERVER['HTTP_HOST'].'/'.$tmpURL.'/';

    else

// else if protocol is https

      $base_url .= $tmpURL.'/';

// give return value

return $base_url; 

}

?>

// and test it

echo home_base_url();

输出将是这样的：

local machine : http://localhost/my_website/ or https://myhost/my_website 

public : http://www.my_website.com/ or https://www.my_website.com/

使用您网站的home_base_url功能并定义它index.php

然后你可以使用这个函数通过 url 加载脚本、CSS 和内容

<?php

echo '<script type="text/javascript" src="'.home_base_url().'js/script.js"></script>'."\n";

?>

将创建如下输出：

<script type="text/javascript" src="http://www.my_website.com/js/script.js"></script>

如果这个脚本工作正常，，！

Answer 9

以下代码将减少检查协议的问题。$_SERVER['APP_URL'] 将显示带有协议的域名

$_SERVER['APP_URL'] 将返回protocol://domain（例如：- http://localhost）

$_SERVER['REQUEST_URI'] 用于 url 的其余部分，例如/directory/subdirectory/something/else

 $url = $_SERVER['APP_URL'].$_SERVER['REQUEST_URI'];

输出将是这样的

http://localhost/directory/subdirectory/something/else

Answer 10

试试下面的代码：

$config['base_url'] = ((isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] == "on") ? "https" : "http");
$config['base_url'] .= "://".$_SERVER['HTTP_HOST'];
$config['base_url'] .= str_replace(basename($_SERVER['SCRIPT_NAME']),"",$_SERVER['SCRIPT_NAME']);
echo $config['base_url'];