使用group by并加入sequelize

Question

我在PostgreSQL数据库上有两个表,合同和付款.一份合同已完成多笔付款.

我有以下两种型号:

 module.exports = function(sequelize, DataTypes) {
  var contracts = sequelize.define('contracts', {
    id: {
      type: DataTypes.INTEGER,
      autoIncrement: true
    }
  }, {
    createdAt: false,
    updatedAt: false,
    classMethods: {
      associate: function(models) {
        contracts.hasMany(models.payments, {
          foreignKey: 'contract_id'
        });
      }
    }
  });


  return contracts;
};

module.exports = function(sequelize, DataTypes) {
  var payments = sequelize.define('payments', {
    id: {
      type: DataTypes.INTEGER,
      autoIncrement: true
    },
    contract_id: {
      type: DataTypes.INTEGER,
    },
    payment_amount: DataTypes.INTEGER,
  }, {
    classMethods: {
      associate: function(models) {
        payments.belongsTo(models.contracts, {
          foreignKey: 'contract_id'
        });
      }
    }
  });


  return payments;
};

我想总结为每份合同支付的所有款项,并使用此功能:

models.contracts.findAll({
    attributes: [
        'id'
    ],
    include: [
    {
        model: models.payments,
        attributes: [[models.sequelize.fn('sum', models.sequelize.col('payments.payment_amount')), 'total_cost']]
    }
    ],
    group: ['contracts.id']
})

但它会生成以下查询:

SELECT "contracts"."id", "payments"."id" AS "payments.id", sum("payments"."payment_amount") AS "payments.total_cost" 
FROM "contracts" AS "contracts" 
LEFT OUTER JOIN "payments" AS "payments" ON "contracts"."id" = "payments"."contract_id" GROUP BY "contracts"."id";

我没有要求选择payments.id,因为我必须按功能将它包含在我的聚合或组中,如我所犯的错误中所述:

可能未处理的SequelizeDatabaseError:错误:列"payments.id"必须出现在GROUP BY子句中或用于聚合函数

我在这里错过了什么吗？我正在按照这个答案,但即使在那里我也不明白SQL请求是如何有效的.

Answer 1

此问题已在Sequelize 3.0.1上修复,必须排除所包含模型的主键

attributes: []

并且必须在主模型上完成聚合(此github问题中的信息).

因此,对于我的用例,代码如下

models.contracts.findAll({
    attributes: ['id', [models.sequelize.fn('sum', models.sequelize.col('payments.payment_amount')), 'total_cost']],
    include: [
    {
        model: models.payments,
        attributes: []
    }
    ],
    group: ['contracts.id']
})

Answer 2

尝试

group: ['contracts.id', 'payments.id']