Android-弹出窗口未分段显示

Question

我正在创建一个，popupWindow但是Fragment调用它时却没有显示。
这是我的popupWindow代码：

LayoutInflater layoutInflater = 
            (LayoutInflater)getActivity()
            .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    View popupView = layoutInflater.inflate(R.layout.popup, null);
    final PopupWindow popupWindow = new PopupWindow(
            popupView, LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);


    Button btnDismiss = (Button)popupView.findViewById(R.id.dismiss);
    btnDismiss.setOnClickListener(new Button.OnClickListener(){

        @Override
        public void onClick(View v) {
            popupWindow.dismiss();
        }});

    popupWindow.showAsDropDown(getView());
    //popupWindow.showAsDropDown(btnOpenPopup, 50, -30);
    //popupWindow.showAsDropDown(getCurrentFocus());
    popupView.setOnTouchListener(new OnTouchListener() {
        int orgX, orgY;
        int offsetX, offsetY;

        @Override
        public boolean onTouch(View v, MotionEvent event) {
            switch (event.getAction()) {
            case MotionEvent.ACTION_DOWN:
                orgX = (int) event.getX();
                orgY = (int) event.getY();
                break;
            case MotionEvent.ACTION_MOVE:
                offsetX = (int)event.getRawX() - orgX;
                offsetY = (int)event.getRawY() - orgY;
                popupWindow.update(offsetX, offsetY, -1, -1, true);
                break;
            }
            return true;
        }});

Answer 1

以下代码可能符合您的要求。从分配给View的OnClickListener的onClick（View v）内部调用此方法：

public void showPopup(View anchorView) {

    View popupView = getLayoutInflater().inflate(R.layout.popup_layout, null);

    PopupWindow popupWindow = new PopupWindow(popupView, 
                           LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);

    // Example: If you have a TextView inside `popup_layout.xml`    
    TextView tv = (TextView) popupView.findViewById(R.id.tv);

    tv.setText(....);

    // Initialize more widgets from `popup_layout.xml`
    ....
    ....

    // If the PopupWindow should be focusable
    popupWindow.setFocusable(true);

    // If you need the PopupWindow to dismiss when when touched outside 
    popupWindow.setBackgroundDrawable(new ColorDrawable());

    int location[] = new int[2];

    // Get the View's(the one that was clicked in the Fragment) location
    anchorView.getLocationOnScreen(location);

    // Using location, the PopupWindow will be displayed right under anchorView
    popupWindow.showAtLocation(anchorView, Gravity.NO_GRAVITY, 
                                     location[0], location[1] + anchorView.getHeight());

}

这里anchorView是onClick（View v）的v。

Answer 2

使用以下代码显示弹出窗口。它将为您工作。

View popupView = layoutInflater.inflate(R.layout.popup, null);
    final PopupWindow popupWindow = new PopupWindow(
            popupView, LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);
popupWindow.showAtLocation(popupView , Gravity.CENTER, 0, 0);