nis*_*tcm 5 uiimagepickercontroller ipad uipopovercontroller
我正在使用此代码打开带有imagepicker的popover
-(IBAction)photosAction:(id)sender
{
// dismiss any left over popovers here
UIImagePickerController* picker = [[UIImagePickerController alloc] init];
picker.sourceType = UIImagePickerControllerSourceTypePhotoLibrary;
picker.delegate = self;
UIPopoverController *popover = [[UIPopoverController alloc] initWithContentViewController:picker];
self.popoverController = popover;
popoverController.delegate = self;
[popoverController presentPopoverFromBarButtonItem:sender permittedArrowDirections:UIPopoverArrowDirectionUp animated:YES];
[picker release];
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但这会导致成员'popoverController'的错误请求,而不是结构或联合,并且此错误'popoverController'未声明(首先在此函数中使用).
此外,我想在选择图像时关闭弹出窗口.
选择图像后,我应该在以下函数中放置什么代码来关闭弹出窗口.
- (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info {
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谢谢您的帮助!
小智 7
该错误意味着尚未在视图控制器中声明popoverController.您需要将其作为ivar和属性添加到接口(它不是内置的):
@interface ... {
...
UIPopoverController *popoverController;
}
@property (nonatomic, retain) UIPopoverController *popoverController;
@end
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在实现中,添加@synthesize,在viewDidUnload中将其设置为nil,并在dealloc中释放.
要解雇popover,你可以调用dismissPopoverAnimated : .
[self.popoverController dismissPopoverAnimated:YES];
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