使用spark将POST主体解析为java对象

Question

我从春天迁移到火花前,现在我陷入了基本的困境.

当我发出POST请求在正文中发送数据时,我希望将JAVA对象放回控制器中.

在春天我曾经做过

@RequestBody User user

它被自动"填充"了..

现在有火花我有方法:

request.body();

但是这给了我一个像这样的序列化字符串:

id=7&name=Pablo+Mat%C3%ADas&lastname=Gomez&githubUsername=pablomatiasgomez

那么我怎样才能获得用户DTO？

当然,User类具有属性

• ID
• 名称
• 姓
• githubUsername

Answer 1

AFAIK,Spark不提供此功能.当我将它用于一个小型宠物项目时,我编写了一些小的实用程序方法来将URL编码的字符串解析为POJO,如下所示:

import com.google.gson.Gson;
import java.io.UnsupportedEncodingException;
import java.net.URLDecoder;
import java.util.LinkedHashMap;
import java.util.Map;

public class Test {

  private static final Gson GSON = new Gson();

  public static <T> T convert(String urlencoded, Class<T> type) {
    try {
      Map<String, Object> map = asMap(urlencoded);
      String json = GSON.toJson(map);
      return GSON.fromJson(json, type);
    }
    catch (Exception e) {
      e.printStackTrace(); // TODO log
      return null;
    }
  }

  public static Map<String, Object> asMap(String urlencoded) throws UnsupportedEncodingException {
    return asMap(urlencoded, "UTF-8");
  }

  @SuppressWarnings("unchecked")
  public static Map<String, Object> asMap(String urlencoded, String encoding) throws UnsupportedEncodingException {

    Map<String, Object> map = new LinkedHashMap<>();

    for (String keyValue : urlencoded.trim().split("&")) {

      String[] tokens = keyValue.trim().split("=");
      String key = tokens[0];
      String value = tokens.length == 1 ? null : URLDecoder.decode(tokens[1], encoding);

      String[] keys = key.split("\\.");
      Map<String, Object> pointer = map;

      for (int i = 0; i < keys.length - 1; i++) {

        String currentKey = keys[i];
        Map<String, Object> nested = (Map<String, Object>) pointer.get(keys[i]);

        if (nested == null) {
          nested = new LinkedHashMap<>();
        }

        pointer.put(currentKey, nested);
        pointer = nested;
      }

      pointer.put(keys[keys.length - 1], value);
    }

    return map;
  }

  public static void main(String[] args) {
    String payload = "id=7&name=Pablo+Mat%C3%ADas&lastname=Gomez&githubUsername=pablomatiasgomez";
    User user = convert(payload, User.class);
    System.out.println(user);
  }
}

class User {

  long id;
  String name;
  String lastname;
  String githubUsername;

  @Override
  public String toString() {
    return "User{" +
        "id=" + id +
        ", name='" + name + '\'' +
        ", lastname='" + lastname + '\'' +
        ", githubUsername='" + githubUsername + '\'' +
        '}';
  }
}

运行此类Test将在控制台上打印以下内容:

User{id=7, name='Pablo Matías', lastname='Gomez', githubUsername='pablomatiasgomez'}

请注意,当a中User有嵌套结构时,例如Address由一个由其他几个字段组成的结构时,这也可以工作.jus将字段与"."这样的字段分开:

public class Test {

  // ... same code ...

  public static void main(String[] args) {
    String payload = "id=7&name=Pablo+Mat%C3%ADas&lastname=Gomez&githubUsername=pablomatiasgomez&" +
        "address.street=Coolsingel&address.number=42a&address.city=Rotterdam";
    User user = convert(payload, User.class);
    System.out.println(user);
  }
}

class User {

  long id;
  String name;
  String lastname;
  String githubUsername;
  Address address;

  @Override
  public String toString() {
    return "User{" +
        "\n  id=" + id +
        "\n  name='" + name + '\'' +
        "\n  lastname='" + lastname + '\'' +
        "\n  githubUsername='" + githubUsername + "'" +
        "\n  address=" + address + "\n" +
        '}';
  }
}

class Address {


  String street;
  String number;
  String city;

  @Override
  public String toString() {
    return "Address{" +
        "street='" + street + '\'' +
        ", number='" + number + '\'' +
        ", city='" + city + '\'' +
        '}';
  }
}

将打印:

User{
  id=7
  name='Pablo Matías'
  lastname='Gomez'
  githubUsername='pablomatiasgomez'
  address=Address{street='Coolsingel', number='42a', city='Rotterdam'}
}

编辑

如果有效负载包含一个列表,比如Users,你可以这样做:

public class Test {

  private static final Gson GSON = new Gson();

  public static <T> T convert(String urlencoded, Type type) {
    try {
      Map<String, Object> map = asMap(urlencoded);
      String json = GSON.toJson(containsList(map) ? map.values() : map);
      return GSON.fromJson(json, type);
    }
    catch (Exception e) {
      e.printStackTrace();
      return null;
    }
  }

  private static boolean containsList(Map<String, Object> map) {
    return !map.isEmpty() && new ArrayList<>(map.keySet()).get(0).contains("[");
  }

  public static Map<String, Object> asMap(String urlencoded) throws UnsupportedEncodingException {
    return asMap(urlencoded, "UTF-8");
  }

  @SuppressWarnings("unchecked")
  public static Map<String, Object> asMap(String urlencoded, String encoding) throws UnsupportedEncodingException {

    Map<String, Object> map = new LinkedHashMap<>();

    for (String keyValue : urlencoded.trim().split("&")) {

      String[] tokens = keyValue.trim().split("=");
      String key = tokens[0];
      String value = tokens.length == 1 ? null : URLDecoder.decode(tokens[1], encoding);

      String[] keys = key.split("\\.");
      Map<String, Object> pointer = map;

      for (int i = 0; i < keys.length - 1; i++) {

        String currentKey = keys[i];
        Map<String, Object> nested = (Map<String, Object>) pointer.get(keys[i]);

        if (nested == null) {
          nested = new LinkedHashMap<>();
        }

        pointer.put(currentKey, nested);
        pointer = nested;
      }

      pointer.put(keys[keys.length - 1], value);
    }

    return map;
  }

  public static void main(String[] args) throws Exception {

    String payload = "id=7&name=Pablo Mat%C3%ADas";
    User user = convert(payload, User.class);
    System.out.println("single user   -> " + user);

    payload = "users[0].id=7&users[0].name=Pablo Mat%C3%ADas&users[1].id=42&users[1].name=Bart";
    List<User> users = convert(payload, new TypeToken<List<User>>(){}.getType());
    System.out.println("list of users -> : " + users);
  }
}

class User {

  long id;
  String name;

  @Override
  public String toString() {
    return "User{" +
        "id=" + id +
        ", name='" + name + '\'' +
        '}';
  }
}

将打印:

single user   -> User{id=7, name='Pablo Matías'}
list of users -> : [User{id=7, name='Pablo Matías'}, User{id=42, name='Bart'}]