基于构建类型和风格的Gradle依赖性

Question

我有几种构建类型:debug, release. 我也有两种口味pub和dev.

pub调味的应用程序取决于pub库,类似的dev味道.现在,我希望debug构建类型应用程序依赖于debug库的构建.以下不起作用:

pubReleaseCompile project(path: ':common', configuration: "pubRelease")
devReleaseCompile project(path: ':common', configuration: "devRelease")
pubDebugCompile project(path: ':common', configuration: "pubDebug")
devDebugCompile project(path: ':common', configuration: "devDebug")

注意:库已设置为编译所有变体.

有没有办法根据flavor和build类型指定条件项目依赖？

编辑:为避免混淆,请遵循build.gradle我目前正在使用的项目中的相关文件.

project/common/build.gradle(库)

apply plugin: 'com.android.library'
apply plugin: 'com.jakewharton.hugo' // annotation-based code generated logs only in debug build

android {
  defaultPublishConfig "pubRelease"
  publishNonDefault true // four variants of the library are built

  buildTypes {
    debug {}
    release {
      minifyEnabled false
      proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.txt'
    }
  }
  productFlavors {
    pub {
      // custom build config fields
    }
    dev {
      // custom build config fields
    }
  }
}

dependencies {
  // ...
}

project/parent/build.gradle(使用该库的应用程序模块之一)

apply plugin: 'com.android.application'
apply plugin: 'com.jakewharton.hugo'

android {
  // ...

  signingConfigs {
    release {
      // ...
    }
  }

  buildTypes {
    release {
      signingConfig signingConfigs.release
      proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-project.txt'
      shrinkResources true
      minifyEnabled true
    }
    debug {
      versionNameSuffix '-debug'
    }
  }
  productFlavors {
    pub {
      // custom res values
    }
    dev {
      // custom res values
    }
  }
}

dependencies {
  // ...
  pubCompile project(path: ':common', configuration: "pubRelease")
  devCompile project(path: ':common', configuration: "devRelease")
}

Answer 1

适用于Gradle 3.0.0的Android插件

构建插件3.0.0使用变体感知依赖项解析,因此devDebug应用程序模块的devDebug变体将自动使用其库模块依赖项的变体.要回答这个问题,这就足够了:

implementation project(':common')

在这里阅读更多内容:https://developer.android.com/studio/build/gradle-plugin-3-0-0-migration.html#variant_aware

原始答案

我能在这里找到解决方案:https://github.com/JakeWharton/u2020/blob/master/build.gradle

有关原始代码不足的原因,请访问:https://code.google.com/p/android/issues/detail？id = 162285

工作方案:

configurations {
  pubDebugCompile
  devDebugCompile
  pubReleaseCompile
  devReleaseCompile
}

dependencies {
  pubReleaseCompile project(path: ':common', configuration: "pubRelease")
  devReleaseCompile project(path: ':common', configuration: "devRelease")
  pubDebugCompile project(path: ':common', configuration: "pubDebug")
  devDebugCompile project(path: ':common', configuration: "devDebug")
}

Answer 2

首先定义各种构建类型:

buildTypes {
    pubRelease {
        //config
    }
    devRelease {
        //config
    }
}

创建仅针对特定buildType和flavor执行的任务:

task pubReleaseTask << {
    //code
}

task devReleaseTask << {
    //code
}

您可以动态添加依赖项:

tasks.whenTaskAdded { task ->
    if (task.name == 'pubRelease') {
        task.dependsOn pubReleaseTask
    }
    if (task.name == 'devRelease') {
        task.dependsOn devReleaseTask 
    }
}