如何通过一个查询从上一小时,最后一天和上个月获取数据？

Question

我正在记录已经发送到我的API的查询,如下所示:

id  |  timestamp
----+---------------------
1   |  2015-01-19 18:01:47
2   |  2015-01-19 20:41:37
3   |  2015-01-20 14:15:06
4   |  2015-01-21 13:02:51
5   |  2015-01-23 05:02:12

现在,我需要知道在过去的60分钟,24小时和30天内进行了多少查询,并将其分组:

HOURLY | DAILY | MONTHLY
-------+-------+--------
0      | 1     | 5

这可以在一个查询中执行吗？

编辑:

我已经使用了这里的建议,并对逻辑事物进行了一些调整,直到它按照我想要的方式工作.

SELECT SUM(CASE WHEN DATE_SUB(NOW(), interval 1 HOUR) <= `TIMESTAMP` THEN 1 ELSE 0 END) HOURLY,
       SUM(CASE WHEN DATE_SUB(NOW(), interval 1 DAY) <= `TIMESTAMP` THEN 1 ELSE 0 END) DAILY,
       SUM(CASE WHEN DATE_SUB(NOW(), interval 1 MONTH) <= `TIMESTAMP` THEN 1 ELSE 0 END) MONTHLY
FROM `REQUESTS`;

非常感谢你的帮助!

Answer 1

select sum(timestamp >= now() - interval 1 hour) as hour,
       sum(timestamp >= now() - interval 1 day) as day,
       sum(timestamp >= now() - interval 1 month) as month
from your_table

SQLFiddle演示

Answer 2

select sum(case when timestamp between now() - interval 1 hour and now() then 1 else 0) hourly,
       sum(case when timestamp between now() - interval 1 day and now() then 1 else 0) daily,
       sum(case when timestamp between now() - interval 1 month and now() then 1 else 0) monthly
from   your_table

编辑...