C++模仿命令

Question

如何实现ls"filename_ [0-5] [3-4]？" 喜欢上课？结果我想存储在向量中.

目前我正在使用调用ls的system(),但这在MS下是不可移植的.

谢谢,阿曼.

Answer 1

以下程序列出当前目录中名称与正则表达式匹配的文件filename_[0-5][34]:

#include <boost/filesystem.hpp>
#include <boost/regex.hpp>  // also functional,iostream,iterator,string
namespace bfs = boost::filesystem;

struct match : public std::unary_function<bfs::directory_entry,bool> {
    bool operator()(const bfs::directory_entry& d) const {
        const std::string pat("filename_[0-5][34]");
        std::string fn(d.filename());
        return boost::regex_match(fn.begin(), fn.end(), boost::regex(pat));
    }
};

int main(int argc, char* argv[])
{
    transform_if(bfs::directory_iterator("."), bfs::directory_iterator(),
                 std::ostream_iterator<std::string>(std::cout, "\n"),
                 match(),
                 mem_fun_ref(&bfs::directory_entry::filename));
    return 0;
}

transform_if()为简洁起见,我省略了定义.它不是标准功能,但应该直接实现.