使用带有Compojure的javax.servlet.Filter

Question

我正在尝试使用Clojure/Compojure构建一个简单的Web站点,并希望将servlet过滤器应用于请求/响应(即标准的javax.servlet.Filter实例).

例如,如果当前的源代码是:

(defroutes my-app
  (GET "/*"
    (html [:h1 "Hello Foo!!"]))
)

我想添加一个这样的过滤器:

(defroutes my-app
  (GET "/*"
    (FILTER my-filter-name
      (html [:h1 "Hello Foo!!"])))
)

其中my-filter-name是javax.servlet.Filter的任意实例.

知道如何有效和优雅地做到这一点？

Answer 1

好的,我现在有这个工作!感谢cgrand指向正确方向的指针!

我的解决方案涉及为过滤的servlet和过滤器链创建代理.以下代码对任何感兴趣的人

(def pass-through-filter 
  (proxy [javax.servlet.Filter] []
    (doFilter
      [request response #^javax.servlet.FilterChain filterchain]
      (do
        (.doFilter filterchain request response)))))

(defn filter-chain 
  [#^javax.servlet.Servlet servlet]
  (proxy [javax.servlet.FilterChain] []
    (doFilter
      [request response]
      (.service servlet request response))))

(defn filtered-servlet 
  [#^javax.servlet.Filter servlet-filter handler]
  (let [#^javax.servlet.Servlet base-servlet (servlet handler)
        the-filter-chain (filter-chain base-servlet)]
    (proxy [javax.servlet.http.HttpServlet] []
      (service
        [request response] 
        (.doFilter servlet-filter request response the-filter-chain))
      (init
        [config] 
        (.init base-servlet config)))))

(defroutes my-app
  (GET "/*"
    (html 
      [:h1 "Hello Foo!!"]))
  (ANY "*"
    [404 "Page not found"]))

(run-server {:port 80}
  "/*" (filtered-servlet pass-through-filter my-app))