Object o = ?
if ((o instanceof Integer) || (o instanceof Double) || (o instanceof Float)|| (o instanceof Long))
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是否有更短的版本来检查对象是否是任何数字类型?
Pet*_*rey 25
你可以做
if (o instanceof Number) {
Number num = (Number) o;
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如果你只有班级,你可以做
Class clazz = o.getClass();
if (Number.class.isAssignableFrom(clazz)) {
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注:此治疗Byte,Short,BigInteger并BigDecimal为数字.
如果您查看Javadoc for Integer,您可以看到它的父元素是Number,而它又具有子类,AtomicInteger, AtomicLong, BigDecimal, BigInteger, Byte, Double, DoubleAccumulator, DoubleAdder, Float, Integer, Long, LongAccumulator, LongAdder, Short因此instance Number将匹配其中任何一个.