我对MySQL的了解不是很深入.如果我有两个表,例如看起来像这样:
Table1
Date v1 v2 v3
05/01/2010 26 abc 45
05/02/2010 31 def 25
05/03/2010 50 ghi 46
Table2
Date v1 v2 v3
05/01/2010 42 jkl 15
05/02/2010 28 mno 14
05/03/2010 12 pqr 64
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我如何按日期加入查询并获得table1.v1和table2.v1的总和,还有table1.v3和table2.v3的总和?V2应该被忽略.
您可能想要执行以下操作:
SELECT t1.date, t1.v1 + t2.v1 AS v1_sum,
t1.v3 + t2.v3 AS v3_sum
FROM table1 t1
JOIN table2 t2 ON (t1.date = t2.date);
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如果您想要两列的总聚合,您还可以执行以下操作:
SELECT SUM(t1.v1 + t2.v1) AS v1_sum,
SUM(t1.v3 + t2.v3) AS v3_sum
FROM table1 t1
JOIN table2 t2 ON (t1.date = t2.date);
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测试用例:
CREATE TABLE table1 (`date` date, `v1` int, `v3` int);
CREATE TABLE table2 (`date` date, `v1` int, `v3` int);
INSERT INTO table1 VALUES ('2010-05-01', 26, 45);
INSERT INTO table1 VALUES ('2010-05-02', 31, 25);
INSERT INTO table1 VALUES ('2010-05-03', 50, 46);
INSERT INTO table2 VALUES ('2010-05-01', 42, 15);
INSERT INTO table2 VALUES ('2010-05-02', 28, 14);
INSERT INTO table2 VALUES ('2010-05-03', 12, 64);
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第一个查询结果:
+------------+--------+--------+
| date | v1_sum | v3_sum |
+------------+--------+--------+
| 2010-05-01 | 68 | 60 |
| 2010-05-02 | 59 | 39 |
| 2010-05-03 | 62 | 110 |
+------------+--------+--------+
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第二个查询结果:
+--------+--------+
| v1_sum | v3_sum |
+--------+--------+
| 189 | 209 |
+--------+--------+
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