Nis*_*ha 1 sql oracle sequence oracle11g
如何在oracle的现有列中添加自动增量?列已经创建,它是表的主键.只想将表改为自动增量.以下是列详细信息
Column Name DATA_TYPE NULLABLE
SEQ_ID VARCHAR2(9 BYTE) No
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自动增量数应从150111111开始到150111112,150111113等值
谢谢
在11g和之前,创建一个序列以通过触发器增加列.请参阅Pre 12c版本中的自动增量主键(标识功能)
例如,
表
SQL> CREATE TABLE t (
2 ID NUMBER(10) NOT NULL,
3 text VARCHAR2(50) NOT NULL);
Table created.
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由序列填充的PRIMARY KEY
SQL> ALTER TABLE t ADD (
2 CONSTRAINT id_pk PRIMARY KEY (ID));
Table altered.
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SEQUENCE支持主键
SQL> CREATE SEQUENCE t_seq
2 START WITH 150111111
3 INCREMENT BY 1;
Sequence created.
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TRIGGER如果您不想在INSERT中使用序列,可以通过TRIGGER自动执行.
SQL> CREATE OR REPLACE TRIGGER t_trg
2 BEFORE INSERT ON t
3 FOR EACH ROW
4 WHEN (new.id IS NULL)
5 BEGIN
6 SELECT t_seq.NEXTVAL
7 INTO :new.id
8 FROM dual;
9 END;
10 /
Trigger created.
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插入
SQL> INSERT INTO t(text) VALUES('auto-increment test 1');
1 row created.
SQL> INSERT INTO t(text) VALUES('auto-increment test 2');
1 row created.
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让我们看看我们是否有ID列自动递增所需的值 -
SQL> SELECT * FROM t;
ID TEXT
---------- --------------------------------------------------
150111111 auto-increment test 1
150111112 auto-increment test 2
SQL>
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因此,ID列现在以值150111111开始,并随后插入增加1.
在12c上,使用Identity列.请参阅Oracle 12c中的IDENTITY列自动增量功能
例如,
具有IDENTITY COLUMN的表
SQL> CREATE TABLE t
2 (
3 ID NUMBER GENERATED ALWAYS AS IDENTITY
4 START WITH 150111111 INCREMENT BY 1,
5 text VARCHAR2(50)
6 );
Table created.
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插入
SQL> INSERT INTO t
2 ( text
3 ) VALUES
4 ( 'This table has an identity column'
5 );
1 row created.
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让我们看看我们是否有ID列自动递增所需的值 -
SQL> COLUMN text format A40
SQL> SELECT * FROM t;
ID TEXT
---------- ----------------------------------------
150111111 This table has an identity column
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因此,ID列现在以值150111111开始,并随后插入增加1.
Oracle创建了一个sequence填充identity column.您可以找到它命名为ISEQ$$
SQL> SELECT sequence_name,
2 min_value,
3 max_value,
4 increment_by
5 FROM user_sequences;
SEQUENCE_NAME MIN_VALUE MAX_VALUE INCREMENT_BY
------------------------------ ---------- ---------- ------------
ISEQ$$_94087 1 1.0000E+28 1
SQL>
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有关标识列的更多信息,请使用ALL_TAB_IDENTITY_COLS视图.
SQL> SELECT table_name,
2 column_name,
3 generation_type,
4 identity_options
5 FROM all_tab_identity_cols
6 WHERE owner = 'LALIT'
7 ORDER BY 1,
8 2;
TABLE_NAME COLUMN_NAME GENERATION IDENTITY_OPTIONS
-------------------- ----------- ---------- ----------------------------------------------
T ID ALWAYS START WITH: 150111111, INCREMENT BY: 1,
MAX_VALUE:9999999999999999999999999999,
MIN_VALUE: 1, CYCLE_FLAG: N, CACHE_SIZE: 20,
ORDER_FLAG: N
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