以编程方式关闭netty

Question

我正在使用netty 4.0.24.Final.

我需要以编程方式启动/停止netty服务器.
启动服务器时,线程被阻止

f.channel().closeFuture().sync()

请帮助提供一些提示如何正确执行此操作.下面是Main类调用的EchoServer.谢谢.

package nettytests;

import io.netty.bootstrap.ServerBootstrap;
import io.netty.channel.ChannelFuture;
import io.netty.channel.ChannelInitializer;
import io.netty.channel.ChannelOption;
import io.netty.channel.EventLoopGroup;
import io.netty.channel.nio.NioEventLoopGroup;
import io.netty.channel.socket.SocketChannel;
import io.netty.channel.socket.nio.NioServerSocketChannel;
import io.netty.handler.logging.LogLevel;
import io.netty.handler.logging.LoggingHandler;

public class EchoServer {

    private final int PORT = 8007;
    private EventLoopGroup bossGroup;
    private EventLoopGroup workerGroup;

    public void start() throws Exception {
        // Configure the server.
        bossGroup = new NioEventLoopGroup(1);
        workerGroup = new NioEventLoopGroup(1);
        try {
            ServerBootstrap b = new ServerBootstrap();
            b.group(bossGroup, workerGroup)
             .channel(NioServerSocketChannel.class)
             .option(ChannelOption.SO_BACKLOG, 100)
             .handler(new LoggingHandler(LogLevel.INFO))
             .childHandler(new ChannelInitializer<SocketChannel>() {
                 @Override
                 public void initChannel(SocketChannel ch) throws Exception {
                     ch.pipeline().addLast(new EchoServerHandler());
                 }
             });

            // Start the server.
            ChannelFuture f = b.bind(PORT).sync();

            // Wait until the server socket is closed. Thread gets blocked.
            f.channel().closeFuture().sync();
        } finally {
            // Shut down all event loops to terminate all threads.
            bossGroup.shutdownGracefully();
            workerGroup.shutdownGracefully();
        }
    }

    public void stop(){
        bossGroup.shutdownGracefully();
        workerGroup.shutdownGracefully();
    }
}


package nettytests;

public class Main {
    public static void main(String[] args) throws Exception {
        EchoServer server = new EchoServer();
        // start server
        server.start();

        // not called, because the thread is blocked above
        server.stop();
    }
}

更新: 我以下列方式更改了EchoServer类.我们的想法是在新线程中启动服务器并保留指向EventLoopGroups的链接.这是正确的方法吗？

package nettytests;

import io.netty.bootstrap.ServerBootstrap;
import io.netty.channel.ChannelFuture;
import io.netty.channel.ChannelInitializer;
import io.netty.channel.ChannelOption;
import io.netty.channel.EventLoopGroup;
import io.netty.channel.nio.NioEventLoopGroup;
import io.netty.channel.socket.SocketChannel;
import io.netty.channel.socket.nio.NioServerSocketChannel;
import io.netty.handler.logging.LogLevel;
import io.netty.handler.logging.LoggingHandler;

/**
 * Echoes back any received data from a client.
 */
public class EchoServer {

    private final int PORT = 8007;
    private EventLoopGroup bossGroup;
    private EventLoopGroup workerGroup;

    public void start() throws Exception {
        new Thread(() -> {
            // Configure the server.
            bossGroup = new NioEventLoopGroup(1);
            workerGroup = new NioEventLoopGroup(1);
            Thread.currentThread().setName("ServerThread");
            try {
                ServerBootstrap b = new ServerBootstrap();
                b.group(bossGroup, workerGroup)
                        .channel(NioServerSocketChannel.class)
                        .option(ChannelOption.SO_BACKLOG, 100)
                        .handler(new LoggingHandler(LogLevel.INFO))
                        .childHandler(new ChannelInitializer<SocketChannel>() {
                            @Override
                            public void initChannel(SocketChannel ch) throws Exception {
                                ch.pipeline().addLast(new EchoServerHandler());
                            }
                        });

                // Start the server.
                ChannelFuture f = b.bind(PORT).sync();

                // Wait until the server socket is closed.
                f.channel().closeFuture().sync();
            } catch (InterruptedException e) {
                e.printStackTrace();
            } finally {
                // Shut down all event loops to terminate all threads.
                bossGroup.shutdownGracefully();
                workerGroup.shutdownGracefully();
            }
        }).start();
    }

    public void stop() throws InterruptedException {
        workerGroup.shutdownGracefully();
        bossGroup.shutdownGracefully();
    }
}

Answer 1

一种方法是制作如下:

// once having an event in your handler (EchoServerHandler)
// Close the current channel
ctx.channel().close();
// Then close the parent channel (the one attached to the bind)
ctx.channel().parent().close();

这样做将最终得到以下结果:

// Wait until the server socket is closed. Thread gets blocked.
f.channel().closeFuture().sync();

主要部分无需额外的线程.现在的问题是:什么样的事件？这取决于你...可能在回显处理程序中作为"关闭"的消息将被视为关闭的顺序而不仅仅是"退出",它将变为仅关闭客户端通道.可能是别的......

如果你没有从子通道处理关闭(通过你的处理程序),而是通过另一个进程(例如查找现有的停止文件),那么你需要一个额外的线程来等待这个事件,然后直接在channel.close()哪里例如,通道将是父母(来自f.channel())...

存在许多其他解决方案