kil*_*615 4 java break switch-statement java-8
编辑:谢谢大家的帮助.我能够使用我在前面章节中学到的技巧和你的建议来使它工作.非常感谢!
我决定尝试通过创建简单的文本冒险来巩固我从Java学到的东西:初学者指南.我即将开始涉及类和方法的第4章.前三章讨论了if,for,while,do-while,switch,简单的键盘交互以及break/continue.
我计划在每章后回去并编辑它以使用我学到的新技能.我几乎没有触及表面,我遇到了问题.
// A basic, but hopefully, lengthy text adventure.
class TextAdventure
{
public static void main(String args[])
throws java.io.IOException
{
System.out.println("\t\t BASIC TEXT ADVENTURE");
// variables I need, attributes, classes, character name, player's choice, gold
int str = 0, inte = 0, chr = 0, con = 0, dex = 0, gold;
char charName, choice;
System.out.println("Welcome player! You are about to embark upon a quest in the form of a text adventure.");
System.out.println("You will make choices, fight monsters, and seek treasure. Come back victorious and you");
System.out.println("could quite possibly buy your way into nobility!");
System.out.println();
caseChoice: {
System.out.println("Please select your class:");
System.out.println("1. Warrior");
System.out.println("2. Mage");
System.out.println("3. Rogue");
System.out.println("4. Archer");
choice = (char) System.in.read(); // Get players choice of class
switch(choice)
{
case '1':
System.out.println("You have chosen the Warrior class!");
System.out.println("You're stats are as followed:");
System.out.println("Str: 16");
System.out.println("Int: 11");
System.out.println("Chr: 14");
System.out.println("Con: 15");
System.out.println("Dex: 9");
str = 16;
inte = 11;
chr = 14;
con = 15;
dex = 9;
break;
case '2':
System.out.println("You have chosen the Mage class!");
System.out.println("You're stats are as followed:");
System.out.println("Str: 16");
System.out.println("Int: 11");
System.out.println("Chr: 14");
System.out.println("Con: 15");
System.out.println("Dex: 9");
str = 9;
inte = 16;
chr = 14;
con = 15;
dex = 11;
break;
case '3':
System.out.println("You have chosen the Rogue class!");
System.out.println("You're stats are as followed:");
System.out.println("Str: 16");
System.out.println("Int: 11");
System.out.println("Chr: 14");
System.out.println("Con: 15");
System.out.println("Dex: 9");
str = 15;
inte = 11;
chr = 14;
con = 9;
dex = 16;
break;
case '4':
System.out.println("You have chosen the Archer class!");
System.out.println("You're stats are as followed:");
System.out.println("Str: 16");
System.out.println("Int: 11");
System.out.println("Chr: 14");
System.out.println("Con: 15");
System.out.println("Dex: 9");
str = 9;
inte = 11;
chr = 14;
con = 15;
dex = 16;
break;
default:
System.out.println("Not a valid choice, please enter a digit 1-4");
break caseChoice;
}
}
}
}
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切换中的默认语句的目的是将代码流返回到类选择中.我没有收到编译错误或运行时错误.当您选择除1,2,3或4之外的任何内容时.它表示"不是一个有效的选择,请输入数字1-4",就像它想象的那样,但程序结束.
我不允许在交换机中使用这样的标签吗?或者它不起作用,因为它在技术上超出了代码块?
was*_*ren 12
我相信你在问题中描述的是某种goto功能,而不是Java中标签的工作方式.
不幸的是, Java 支持标签.Oracle的这篇文章对此进行了描述.
所以,基本上你可以有带标签的循环,你可以使用关键字continue,break依此类推来控制循环的流程.
以下示例说明了如何将循环与break关键字一起使用.当break被调用其终止标记语句即语句后面someLabel.它不会返回执行指定标签的位置.
someLabel:
for (i = 0; i < 100; i++) {
for (j = 0; j < 100; j++) {
if (i % 20 == 0) {
break someLabel;
}
}
}
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该continue关键字处理标签的方法.当您调用时continue someLabel;,外循环将继续.
由于按照该SO-问题,你也可以做结构是这样的:
BlockSegment:
if (conditionIsTrue) {
doSomeProcessing ();
if (resultOfProcessingIsFalse()) break BlockSegment;
otherwiseDoSomeMoreProcessing();
// These lines get skipped if the break statement
// above gets executed
}
// This is where you resume execution after the break
anotherStatement();
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所以,基本上如果你break在你的标签中switch会破坏整个语句会发生什么(而不是跳到语句的开头).
您可以通过运行以下程序进一步测试标签.如果你输入"quit",它会打破while循环,否则它会破坏开关.
public static void main(String... args) {
programLoop:
{
while (true) {
Scanner scanner = new Scanner(System.in);
final String input = scanner.next();
switch (input) {
case "quit":
break programLoop; // breaks the while-loop
default:
break; // break the switch
}
System.out.println("After the switch");
}
}
}
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就个人而言,我需要一个非常特殊的情况才能推荐使用标签.我发现,如果您重新安排代码以便不需要标签(例如将复杂代码分解为较小的函数),代码就会更容易理解.