Python编码/解码问题

Question

如何将此字符串"wasn\xe2\x80\x99t"解码回正常编码.

所以这个词实际上不是,而不是"不是\ xe2\x80\x99t"？例如:

print "\xe2\x80\x9cThings"
string = "\xe2\x80\x9cThings"
print string.decode('utf-8')
print string.encode('ascii', 'ignore')

“Things
“Things
Things

但我其实想要"事情.

要么:

print "weren\xe2\x80\x99t"
string = "weren\xe2\x80\x99t"
print string.decode('utf-8')
print string.encode('ascii', 'ignore')

weren’t
weren’t
werent

但我实际上想得到的不是.

我该怎么办？

Answer 1

我绘制了最常见的奇怪字符,所以这是基于Oliver W.答案的完全答案.

这个功能绝不是理想的,但它是最好的开始.有更多的字符定义:

http://utf8-chartable.de/unicode-utf8-table.pl?start=8192&number=128&utf8=string
http://www.utf8-chartable.de/unicode-utf8-table.pl?start=128&number=128&names = - &UTF8 =字串文本

...

def unicodetoascii(text):

    uni2ascii = {
            ord('\xe2\x80\x99'.decode('utf-8')): ord("'"),
            ord('\xe2\x80\x9c'.decode('utf-8')): ord('"'),
            ord('\xe2\x80\x9d'.decode('utf-8')): ord('"'),
            ord('\xe2\x80\x9e'.decode('utf-8')): ord('"'),
            ord('\xe2\x80\x9f'.decode('utf-8')): ord('"'),
            ord('\xc3\xa9'.decode('utf-8')): ord('e'),
            ord('\xe2\x80\x9c'.decode('utf-8')): ord('"'),
            ord('\xe2\x80\x93'.decode('utf-8')): ord('-'),
            ord('\xe2\x80\x92'.decode('utf-8')): ord('-'),
            ord('\xe2\x80\x94'.decode('utf-8')): ord('-'),
            ord('\xe2\x80\x94'.decode('utf-8')): ord('-'),
            ord('\xe2\x80\x98'.decode('utf-8')): ord("'"),
            ord('\xe2\x80\x9b'.decode('utf-8')): ord("'"),

            ord('\xe2\x80\x90'.decode('utf-8')): ord('-'),
            ord('\xe2\x80\x91'.decode('utf-8')): ord('-'),

            ord('\xe2\x80\xb2'.decode('utf-8')): ord("'"),
            ord('\xe2\x80\xb3'.decode('utf-8')): ord("'"),
            ord('\xe2\x80\xb4'.decode('utf-8')): ord("'"),
            ord('\xe2\x80\xb5'.decode('utf-8')): ord("'"),
            ord('\xe2\x80\xb6'.decode('utf-8')): ord("'"),
            ord('\xe2\x80\xb7'.decode('utf-8')): ord("'"),

            ord('\xe2\x81\xba'.decode('utf-8')): ord("+"),
            ord('\xe2\x81\xbb'.decode('utf-8')): ord("-"),
            ord('\xe2\x81\xbc'.decode('utf-8')): ord("="),
            ord('\xe2\x81\xbd'.decode('utf-8')): ord("("),
            ord('\xe2\x81\xbe'.decode('utf-8')): ord(")"),

                            }
    return text.decode('utf-8').translate(uni2ascii).encode('ascii')

print unicodetoascii("weren\xe2\x80\x99t")  

Answer 2

在 Python 3 中我会这样做：

string = "\xe2\x80\x9cThings"
bytes_string = bytes(string, encoding="raw_unicode_escape")
happy_result = bytes_string.decode("utf-8", "strict")
print(happy_result)

不需要翻译地图，只需代码:)