基本的ng-grid示例不起作用

use*_*707 4 angularjs ng-grid

我是angularjs和ng-grid的新手......我目前正在通过一个简单的ng-grid示例,但我似乎无法让它工作.

这是我的HTML:

<!DOCTYPE html>
<html ng-app="myApp">
<head lang="en">
<meta charset="utf-8">
<title>Getting Started With ngGrid Example</title>
<link rel="stylesheet" type="text/css" href="https://cdnjs.cloudflare.com/ajax/libs/ng-grid/2.0.11/ng-grid.css" data-semver="2.0.11" data-require="ng-grid@*" />
<link rel="stylesheet" type="text/css" href="css/style.css" />
<script src="//cdnjs.cloudflare.com/ajax/libs/jquery/2.1.1/jquery.min.js" data-semver="2.1.1" data-require="jquery@*"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/angular.js/1.3.7/angular.js" data-semver="1.3.7" data-require="angular.js@*"></script>
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/ng-grid/2.0.11/ng-grid.min.js" data-semver="2.0.11" data-require="ng-grid@*"></script>
<script src="js/controllers.js"></script>
</head>
<body ng-controller="MyCtrl">
<h1>{{title}}</h1>
<div class="gridStyle" ng-grid="gridOptions">
</div>
</body>
</html>
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这是我的js:

'use strict';

var app = angular.module('myApp', ['ui.grid']);
app.controller('MyCtrl', function($scope) {
  $scope.myData = [{name: "Moroni", age: 50},
  {name: "Tiancum", age: 43},
  {name: "Jacob", age: 27},
  {name: "Nephi", age: 29},
  {name: "Enos", age: 34}];
  $scope.gridOptions = { data: 'myData' };
  $scope.title = "ng-grid example";
});
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我还在Plunker中创建了一个我的问题示例:http://plnkr.co/edit/9fEF8sBAMhaMxWimLfTn?p = preview

谢谢!

莎娜

Pat*_*ard 10

您在此处找到文档的文档错误地指出了以下内容

var app = angular.module('myApp', ['ui.grid']); 
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它们在同一页面上的plunkr链接具有正确的语法

var app = angular.module('myApp', ['ngGrid']);
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这里找到.