在Objective-C中解析ISO8601日期(iPhone OS SDK)

Question

如何将"2010-04-30T00:45:48.711127"解析为NSDate？(并保持所有精度)

Answer 1

NSDate 似乎只有毫秒精度。

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#import <Foundation/Foundation.h>\n\nint main (int argc, const char * argv[]) {\n    NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init];\n\n    NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];\n    [dateFormatter setDateFormat:@"yyyy-MM-dd\'T\'hh:mm:ss.SSSSSS"];\n\n    NSDate *date = [dateFormatter dateFromString:@"2010-04-30T00:45:48.711127"];\n\n    NSLog(@"%@", date);\n\n    NSString *string = [dateFormatter stringFromDate:date];\n\n    NSLog(@"%@", string);\n\n    [pool drain];\n    return 0;\n}\n

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该代码产生以下控制台输出：

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Program loaded.\nrun\n[Switching to process 27202]\nRunning\xe2\x80\xa6\n2010-05-08 20:02:46.342 TestNSDate[27202:a0f] 2010-04-30 00:45:48 -0700\n2010-05-08 20:02:46.344 TestNSDate[27202:a0f] 2010-04-30T12:45:48.711000\n\nDebugger stopped.\nProgram exited with status value:0.\n

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所以"2010-04-30T00:45:48.711127"变成"2010-04-30T00:45:48.711000"可能不是你想要的。

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