编写一个计算(a/1)+(a/2)+(a/3)+(a/4)+ .......... +(a/n)之和的程序

Question

我正在尝试解决这个程序的打印总和:(a/1)+(a/2)+(a/3)+(a/4)+ .......... + (a/n)其中a由用户输入,n的限制也由用户输入,这是我尝试的程序:

/**
 * Program to 
 * 
 * Anirudh Gupta
 * th August 2014
 */
import java.io.*;
public class Program87b
{
   public static void main () throws IOException
   {
       InputStreamReader isr=new InputStreamReader(System.in);
       BufferedReader br= new BufferedReader(isr);
       System.out.println("Enter the value of the numerator");
       double a=Double.parseDouble(br.readLine());
       System.out.println("Enter the limit for the denominator");
       int limit=Integer.parseInt(br.readLine());
       double n=1.0;
       double sum=0.0;
       while(n<=limit)
       {
           sum=+(a/n);
           n++;
       }
       System.out.println(sum);
   }
}

但是当我输入a = 4且n = 5时我得到0.8这只是(4/5)的ans而不是(4/1)+(4/2)+(4/3)+(4的总和/ 4)+(4/5)应该是9.1333333333 ...

Answer 1

改变= +到+ =并且我不确定变量'd'来自哪里,但我相信它应该被替换为'n'

public static void main () throws IOException
   {
       InputStreamReader isr=new InputStreamReader(System.in);
       BufferedReader br= new BufferedReader(isr);

       System.out.println("Enter the value of the numerator");
       double a=Double.parseDouble(br.readLine());

       System.out.println("Enter the limit for the denominator");
       int limit=Integer.parseInt(br.readLine());

       double n=1.0;
       double sum=0.0;

       while(n<=limit)
       {
           sum+=(a/n);
           n++;
       }

       System.out.println(sum);
   }