Nat*_*fer 2 parsing json ios swift
我在我的swift应用程序中有一个api,需要一些额外的授权.服务提供了一些示例,但没有在swift中提供.
我的代码:
let request = NSURLRequest(URL: NSURL(string: "https://www.kimonolabs.com/api/au4sl00w?apikey=iFotcJDm95fB6Ua7XiZRDZA0jl3uYWev")!)
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Pyhton中的示例
import urllib2
request = urllib2.Request("https://www.kimonolabs.com/api/au4sl00w? apikey=iFotcJDm95fB6Ua7XiZRDZA0jl3uYWev", headers={"authorization" : "Bearer A5ve02gq40itf0eoYfT5ny6drZwcysxx"})
contents = urllib2.urlopen(request).read()
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Ruby中的示例
require 'rest_client'
response = RestClient.get('https://www.kimonolabs.com/api/au4sl00w?apikey=iFotcJDm95fB6Ua7XiZRDZA0jl3uYWev', {'authorization' => 'Bearer A5ve02gq40itf0eoYfT5ny6drZwcysxx'});
print(response);
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R中的例子
library('RCurl')
library('rjson')
json <- getURL('https://www.kimonolabs.com/api/au4sl00w?apikey=iFotcJDm95fB6Ua7XiZRDZA0jl3uYWuc',
httpheader = c(authorization='Bearer A5ve02gq40itf0eoYfT5ny6drZwcysxx'))
obj <- fromJSON(json)
print(obj)
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那么,我怎么能在Swift中做到这一点?
修改后的回答:"如何在Swift中发出HTTP请求+基本身份验证".
我相信它看起来像这样(假设你的API_ID是au4sl00w):
let token = "yourToken"
// create the request
let url = NSURL(string: "https://www.kimonolabs.com/api/au4sl00w?apikey=iFotcJDm95fB6Ua7XiZRDZA0jl3uYWev")
let request = NSMutableURLRequest(URL: url)
request.HTTPMethod = "GET"
request.setValue("Bearer \(token)", forHTTPHeaderField: "Authorization")
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并确保创建一个新的访问令牌,现在这个是公开的:)
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