将data.frame的colnames增加1

Question

拥有带有colnames的data.frame

nam <- c("a", paste0("a_", seq(12)))
"a" "a_1" "a_2" "a_3" "a_4" "a_5" "a_6" "a_7" "a_8" "a_9" "a_10" "a_11" "a_12"

如何将数字的数字增加1？

预期结果将是

"a" "a_2" "a_3" "a_4" "a_5" "a_6" "a_7" "a_8" "a_9" "a_10" "a_11" "a_12" "a_13"

到目前为止,我的解决方案看起来非常复杂......是否有比这更简单

increment_names <- function(nam){
  where <- regexpr("\\d", nam)
  ind <- which(where > 0)
  increment <- as.numeric(substring(nam[ind], where[ind])) + 1
  substring(nam[ind], where[ind]) <- as.character(increment)
  nam
}

> increment_names(nam)
 [1] "a" "a_2" "a_3" "a_4" "a_5" "a_6" "a_7" "a_8" "a_9" "a_10" "a_11" "a_12" "a_13"

Answer 1

基础regmatches解决方案

r <- regexpr("\\d+",nam)
regmatches(nam,r) <- as.numeric(regmatches(nam,r))+1
nam
# [1] "a"    "a_2"  "a_3"  "a_4"  "a_5"  "a_6"  "a_7"  "a_8"  ...

Answer 2

使用gsubfn包你可以做一些简单的事情

library(gsubfn) 
gsubfn("\\d+", function(x) as.numeric(x) + 1, nam)
## [1] "a"    "a_2"  "a_3"  "a_4"  "a_5"  "a_6"  "a_7"  "a_8"  "a_9"  "a_10" "a_11" "a_12" "a_13"

这适用于任何模式，并且您不需要假设上面提到的“ nonnumbers_numbers ”模式，例如

(nam <- c("a", paste0(seq(12), "_a")))
## [1] "a"    "1_a"  "2_a"  "3_a"  "4_a"  "5_a"  "6_a"  "7_a"  "8_a"  "9_a"  "10_a" "11_a" "12_a"
gsubfn("\\d+", function(x) as.numeric(x) + 1, nam)
## [1] "a"    "2_a"  "3_a"  "4_a"  "5_a"  "6_a"  "7_a"  "8_a"  "9_a"  "10_a" "11_a" "12_a" "13_a"