我真的不明白我在这里做什么.我有这个页面profesor.php,我想在其中插入一些数据到数据库中.从表单提交数据后,我想重定向到另一个页面insert.php并显示一条消息.所以我有profesor.php:
<?php
session_start();
if (isset($_SESSION['id'])) {
$fullname = $_SESSION['name'];
echo "<h1> Welcome " . $fullname . "</h1>";
} else {
$result = "You are not logged in yet";
}
if (isset($_POST['studname'])) {
include_once("dbConnect.php");
$studname = strip_tags($_POST['studname']);
$course = strip_tags($_POST['course']);
$grade = strip_tags($_POST['grade']);
$getStudidStm = "SELECT userid FROM users WHERE name = '$studname'";
$getStudidQuery = mysqli_query($dbCon, $getStudidStm);
$row = mysqli_fetch_row($getStudidQuery);
$studid = $row[0];
$_SESSION['studid'] = $studid;
$_SESSION['course'] = $course;
$_SESSION['grade'] = $grade;
header("Location: insert.php");
}
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title><?php echo $fullname ;?></title>
</head>
<body>
<div id="wrapper">
<h2>Insert new grade</h2>
<form id="insertForm" action="insert.php" method="post" enctype="multipart/form-data">
Student: <input type="text" name="studname" /> <br />
Course : <input type="text" name="course" /> <br />
Grade : <input type="text" name="grade" /> <br />
<input type="submit" value="Insert" name="Submit" />
</form></div>
</form>
</body>
</html>
和 insert.php
<?php
session_start();
if (isset($_SESSION['studid'])) {
include_once("dbConnect.php");
$studid = $_SESSION['studid'];
$course = $_SESSION['course'];
$grade = $_SESSION['grade'];
echo $studid;
echo $course;
echo $grade;
}
我的问题是insert.php没有显示任何东西.我真的不明白我做错了什么.需要一些帮助.
你的问题在于你的形式:
<form id="insertForm" action="insert.php" [...]
你发送数据,insert.php但所有'魔术'
$_SESSION['studid'] = $studid;
$_SESSION['course'] = $course;
$_SESSION['grade'] = $grade;
你留下来 profesor.php
只需action="insert.php"改为action="profesor.php",它应该工作正常.