来自上传文件的数据

Question

我有一个代码,可以是上传到文件夹的文件数量,我希望这些文件的名称,大小和URL到数据库,但我的控制器不工作.(我使用CakePHP框架).我想添加这些文件数据我上传到数据库(所有文件数据),我得到了错误.

错误:

Notice (8): Undefined index: tmp_nam?€?€‹?€?€‹e [APP\Controller\UploadFilesController.php, line 24]

我的控制器

public function uploadFile() {
        $filename = '';
            if ($this->request->is('post')) {           // checks for the post values
                $uploadData = $this->request->data;
                //print_r($this->request->data); die;
                foreach($uploadData as $file){
                $filename = basename($file['name']); // gets the base name of the uploaded file
                $uploadFolder = WWW_ROOT. 'files';  // path where the uploaded file has to be saved
                $filename = $filename; // adding time stamp for the uploaded image for uniqueness
                $uploadPath =  $uploadFolder . DS . $filename;
                if( !file_exists($uploadFolder) ){
                    mkdir($uploadFolder); // creates folder if  not found
                }
                if (!move_uploaded_file($file['tmp_name'], $uploadPath)) {
                    return false;
                } 
                echo "Sa sisestasid faili: $filename<br>";
            }
             foreach($this->request->data['UploadFile']['file_upload'] as $file){
                if (!empty($this->request->data)  && is_uploaded_file($this->request->data['UploadFile']['file_upload']['tmp_nam????e'])) {  //THIS IS LINE 24
                    $fileData = fread(fopen($this->request->data['UploadFile']['file_upload']['tmp_name'], "r"), $this->request->data['UploadFile']['file_upload']['size']);
                    $this->request->data['UploadFile']['name'] = $this->request->data['UploadFile']['file_upload']['name'];
                    $this->request->data['UploadFile']['size'] = $this->request->data['UploadFile']['file_upload']['size'];
                    $this->request->data['UploadFile']['URL'] = $this->request->data['UploadFile']['file_upload']['tmp_name'];
                    $this->request->data['UploadFile']['data'] = $fileData;
                    $this->UploadFile->create();
                    $this->UploadFile->save($this->request->data);
                }
            }
         }
     }    
    }

这是我的View文件:

<?php
    echo $this->Form->create('uploadFile', array( 'type' => 'file'));
?>

    <div class="input_fields_wrap">

        <label for="uploadFilefiles"></label>
        <input type="file" name="data[]" id="uploadFilefiles">

    </div>

<button type="button" class="add_field_button">+</button> <br><br>

    <form name="frm1" method="post" onsubmit="return greeting()">
        <input type="submit" value="Submit">
    </form>

<?php
echo $this->Html->script('addFile');

如果有必要,我也可以添加AddFile脚本.

这是我的表(upload_files)结构:

Answer 1

我想,这是最好的方法:

public function uploadFile() {
    $filename = '';
        if ($this->request->is('post')) {           // checks for the post values
            $uploadData = $this->request->data ['UploadFile']['file_upload'];
            //print_r($this->request->data); die;
            foreach($uploadData as $file){
                $filename = basename($file['name']); // gets the base name of the uploaded file
                $uploadFolder = WWW_ROOT. 'files';  // path where the uploaded file has to be saved
                $filename = $filename; // adding time stamp for the uploaded image for uniqueness
                $uploadPath =  $uploadFolder . DS . $filename;
                if( !file_exists($uploadFolder) ){
                    mkdir($uploadFolder); // creates folder if  not found
                }
                if (!move_uploaded_file($file['tmp_name'], $uploadPath)) {
                    return false;
                } 
                echo "Sa sisestasid faili: $filename<br>";

                    $this->request->data['UploadFile']['name'] = $file['name'];
                    $this->request->data['UploadFile']['size'] = $file['size'];
                    $this->request->data['UploadFile']['URL'] = $file['tmp_name'];
                    $this->UploadFile->create();
                    $this->UploadFile->save($this->request->data);
            }           
        }
    }

我在我的主人和它的工作中尝试了这个.