服务意图必须是明确的:意图

Question

我现在有一个应用程序,我通过广播接收器(MyStartupIntentReceiver)调用服务.广播接收器中用于呼叫服务的代码是:

public void onReceive(Context context, Intent intent) {
    Intent serviceIntent = new Intent();
    serviceIntent.setAction("com.duk3r.eortologio2.MyService");
    context.startService(serviceIntent);
}

问题是在Android 5.0 Lollipop中我收到以下错误(在以前版本的Android中,一切正常):

Unable to start receiver com.duk3r.eortologio2.MyStartupIntentReceiver: java.lang.IllegalArgumentException: Service Intent must be explicit: Intent { act=com.duk3r.eortologio2.MyService }

为了将服务声明为显式并正常启动,我需要更改什么？尝试在其他类似的线程中的一些答案,但虽然我摆脱了消息,服务将无法启动.

Answer 1

您对应用中的服务,活动等所做的任何意图都应始终遵循此格式

Intent serviceIntent = new Intent(context,MyService.class);
context.startService(serviceIntent);

要么

Intent bi = new Intent("com.android.vending.billing.InAppBillingService.BIND");
bi.setPackage("com.android.vending");

隐式意图(当前代码中包含的内容)被视为安全风险

Answer 2

设置你的packageName作品.

intent.setPackage(this.getPackageName());

Answer 3

将隐式意图转换为显式意图，然后启动服务。

        Intent implicitIntent = new Intent();
        implicitIntent.setAction("com.duk3r.eortologio2.MyService");
        Context context = getApplicationContext();
        Intent explicitIntent = convertImplicitIntentToExplicitIntent(implicitIntent, context);
        if(explicitIntent != null){
            context.startService(explicitIntent);
            }


    public static Intent convertImplicitIntentToExplicitIntent(Intent implicitIntent, Context context) {
            PackageManager pm = context.getPackageManager();
            List<ResolveInfo> resolveInfoList = pm.queryIntentServices(implicitIntent, 0);

            if (resolveInfoList == null || resolveInfoList.size() != 1) {
                return null;
            }
            ResolveInfo serviceInfo = resolveInfoList.get(0);
            ComponentName component = new ComponentName(serviceInfo.serviceInfo.packageName, serviceInfo.serviceInfo.name);
            Intent explicitIntent = new Intent(implicitIntent);
            explicitIntent.setComponent(component);
            return explicitIntent;
        }