使用UNION ALL进行分组和排序

Hel*_*Out 11 sql group-by sql-order-by sql-server-2008 union-all

我有一个存储过程与以下查询:

SELECT (sum(addition)) AS [COUNT], 
MAX(CONVERT(VARCHAR(12),CREATED,102)) as [date]
FROM [TABLE_ONE]
WHERE convert(VARCHAR(12),CREATED,102) BETWEEN CONVERT(date,@startdate) AND CONVERT(date,@enddate)
AND [ServiceID]=@serid
GROUP BY CONVERT(VARCHAR(12),CREATED,102) 
ORDER BY  CONVERT(VARCHAR(12),CREATED,102)  
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我需要做一个union all,所以我可以从两个表中获得结果的总和,并且我希望结果按照相同的方式进行分组和排序.

这不起作用:

SELECT (sum(addition)) AS [COUNT], 
MAX(CONVERT(VARCHAR(12),CREATED,102)) as [date]
FROM [TABLE_ONE]
WHERE convert(VARCHAR(12),CREATED,102) BETWEEN CONVERT(date,@startdate) AND CONVERT(date,@enddate)
AND [ServiceID]=@serid
GROUP BY CONVERT(VARCHAR(12),CREATED,102) 
ORDER BY  CONVERT(VARCHAR(12),CREATED,102)  

UNION ALL

SELECT (sum(addition)) AS [COUNT], 
MAX(CONVERT(VARCHAR(12),CREATED,102)) as [date]
FROM [TABLE_TWO]
WHERE convert(VARCHAR(12),CREATED,102) BETWEEN CONVERT(date,@startdate) AND CONVERT(date,@enddate)
AND [ServiceID]=@serid
GROUP BY CONVERT(VARCHAR(12),CREATED,102) 
ORDER BY  CONVERT(VARCHAR(12),CREATED,102) 
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我想订购整体结果,并按日期分组.

Mur*_*nik 17

你可以申请group byorder by之后union all:

SELECT  (SUM(addition)) AS [COUNT], MAX([date]) AS [max_date]
FROM    (SELECT addition, CONVERT(VARCHAR(12),CREATED,102)) as [date]
         FROM   [TABLE_ONE]
         WHERE  CONVERT(VARCHAR(12),CREATED,102) 
                    BETWEEN CONVERT(date,@startdate) AND 
                            CONVERT(date,@enddate)
                AND [ServiceID]=@serid 
         UNION ALL
         SELECT addition, (CONVERT(VARCHAR(12),CREATED,102)) as [date]
         FROM   [TABLE_TWO]
         WHERE  CONVERT(VARCHAR(12),CREATED,102) 
                    BETWEEN CONVERT(date,@startdate) AND 
                            CONVERT(date,@enddate)
                AND [ServiceID]=@serid) t
GROUP BY [date]
ORDER BY 2
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