这是我的表的摘录:
gid | datepose | pvc
---------+----------------+------------
1 | 1961 | 01
2 | 1949 |
3 | 1990 | 02
1 | 1981 |
1 | | 03
1 | |
Run Code Online (Sandbox Code Playgroud)
我想用SELECT CASE下面的方法填充PVC柱:
SELECT
gid,
CASE
WHEN (pvc IS NULL OR pvc = '') AND datpose < 1980) THEN '01'
WHEN (pvc IS NULL OR pvc = '') AND datpose >= 1980) THEN '02'
WHEN (pvc IS NULL OR pvc = '') AND (datpose IS NULL OR datpose = 0) THEN '03'
END AS pvc
FROM my_table ;
Run Code Online (Sandbox Code Playgroud)
结果是与源表相同的内容,没有发生任何事情,我在pg_log文件中没有得到任何错误消息.它可能是语法错误,或在WHEN子句中使用多个条件的问题?
感谢您的帮助和建议!
小智 130
这种代码也许适合你
SELECT
*,
CASE
WHEN (pvc IS NULL OR pvc = '') AND (datepose < 1980) THEN '01'
WHEN (pvc IS NULL OR pvc = '') AND (datepose >= 1980) THEN '02'
WHEN (pvc IS NULL OR pvc = '') AND (datepose IS NULL OR datepose = 0) THEN '03'
ELSE '00'
END AS modifiedpvc
FROM my_table;
gid | datepose | pvc | modifiedpvc
-----+----------+-----+-------------
1 | 1961 | 01 | 00
2 | 1949 | | 01
3 | 1990 | 02 | 00
1 | 1981 | | 02
1 | | 03 | 00
1 | | | 03
(6 rows)
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
182491 次 |
| 最近记录: |