Mac*_*iej 4 python list python-3.x
打印列表时遇到问题.例如,我有两个列表:
a = [1,2,3,4,5]
b = [6,7,8,9,10]
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现在我想要求用户输入列表名称,然后打印该列表.
name = input("Write a list name")
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用户输入 "a"
for x in name:
print(x)
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但它不起作用(不打印列表"a").你可以帮帮我吗?
更多信息:
我有一本字典:
poland = {"poznan": 86470,
"warszawa": 86484,
"sopot": 95266}
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并列出:
poznan = [1711505, 163780, 932461, 1164703]
warszawa = [1503333, 93311, 93181, 93268, 106958, 106956, 127649, 106801, 107386, 93245, 154078, 107032]
sopot = [228481, 164126, 922891]
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现在如果用户写"poznan"我想从字典中将波兹南的ID分配给变量"city_id",然后打印名为"poznan"的列表
Reu*_*ani 11
您需要将列表映射到字符串,这是用户可以输入的内容.
所以使用字典:
lists_dict = {
'a': [1,2,3,4,5]
'b': [6,7,8,9,10]
}
key = input("Write a list name")
print lists_dict[key]
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您的字典应如下所示:
poland = {
"poznan": {"name": 86470, "lst": [1711505, 163780, 932461, 1164703]},
"warszawa": {"name": 86484, "lst": [1503333, 93311, 93181, 93268, 106958, 106956, 127649, 106801, 107386, 93245, 154078, 107032]},
"sopot": {"name": 95266, "lst": [228481, 164126, 922891]}
}
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访问您的列表应该像这样:
key = input("Write a list name")
# print the list under 'lst' for the dictionary under 'key'
# print poland[key]["lst"]
# EDIT: python 3's print a function, thanks @Ffisegydd:
print(poland[key]["lst"])
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你可以globals()像这样使用字典 print(globals()[name]).input()返回一个名称,因此也不需要使用循环.
>>> a = [1,2,3,4,5]
>>> b = [6,7,8,9,10]
>>> name = input("Write a list name ")
Write a list name a
>>> globals()[name]
[1, 2, 3, 4, 5]
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OP编辑后:
>>> poland = {"poznan": 86470,
... "warszawa": 86484,
... "sopot": 95266}
>>> poznan = [1711505, 163780, 932461, 1164703]
>>> warszawa = [1503333, 93311, 93181, 93268, 106958, 106956, 127649, 106801, 107386, 93245, 154078, 107032]
>>> sopot = [228481, 164126, 922891]
>>> name = input("Enter name: ")
Enter name: poznan
>>> city_id = poland[name]
>>> city_id
86470
>>> globals()[name]
[1711505, 163780, 932461, 1164703]
>>>
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