Python将来五分钟创建unix时间戳

Question

我必须在未来5分钟创建一个"Expires"值,但我必须以UNIX Timestamp格式提供它.到目前为止,我有这个,但它似乎是一个黑客.

def expires():
    '''return a UNIX style timestamp representing 5 minutes from now'''
    epoch = datetime.datetime(1970, 1, 1)
    seconds_in_a_day = 60 * 60 * 24
    five_minutes = datetime.timedelta(seconds=5*60)
    five_minutes_from_now = datetime.datetime.now() + five_minutes
    since_epoch = five_minutes_from_now - epoch
    return since_epoch.days * seconds_in_a_day + since_epoch.seconds

是否有为我进行时间戳转换的模块或函数？

Answer 1

另一种方法是使用calendar.timegm:

future = datetime.datetime.utcnow() + datetime.timedelta(minutes=5)
return calendar.timegm(future.timetuple())

它也比%sflag 更便携strftime(在Windows上不起作用).

Answer 2

现在在Python> = 3.3中,您可以调用timestamp()方法将时间戳作为浮点数.

import datetime
current_time = datetime.datetime.now(datetime.timezone.utc)
unix_timestamp = current_time.timestamp() # works if Python >= 3.3

unix_timestamp_plus_5_min = unix_timestamp + (5 * 60)  # 5 min * 60 seconds

Answer 3

刚发现这个,它甚至更短.

import time
def expires():
    '''return a UNIX style timestamp representing 5 minutes from now'''
    return int(time.time()+300)

Answer 4

这就是你需要的:

import time
import datetime
n = datetime.datetime.now()
unix_time = time.mktime(n.timetuple())

Answer 5

您可以使用格式字符串datetime.strftime来使用Epoch表单获取时间%s:

def expires():
    future = datetime.datetime.now() + datetime.timedelta(seconds=5*60)
    return int(future.strftime("%s"))

Answer 6

这是一个不太破碎datetime的解决方案,可以从datetime对象转换为posix时间戳:

future = datetime.datetime.utcnow() + datetime.timedelta(minutes=5)
return (future - datetime.datetime(1970, 1, 1)).total_seconds()

有关详细信息,请参阅在Python中将datetime.date转换为UTC时间戳.

Answer 7

def in_unix(input):
  start = datetime.datetime(year=1970,month=1,day=1)
  diff = input - start
  return diff.total_seconds()