Rob*_*Rob 10 swift swift-dictionary
我正在尝试实现Dictionary
扩展,我想处理可选值.但无论我做什么,如果我在[String: String?]
字典上使用我的方法,它都无法选择性地绑定值.如何编写优雅处理可选值的字典的扩展?
考虑以下扩展:
extension Dictionary {
func someMethod() {
for (key, value) in self {
if let valueString = value as? String {
println(" \(key) = \(valueString)")
} else {
println(" \(key) = \(value) cannot be cast to `String`")
}
}
}
}
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请考虑以下代码:
let dictionary: [String: AnyObject?] = ["foo": "bar"]
dictionary.someMethod()
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它好奇地报道
foo = Optional(bar) cannot be cast to `String`
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我可以编写一个非扩展方法来处理带有可选值的字典参数,但是看不到如何将它作为扩展名来实现Dictionary
.
你可以通过反思来做到这一点。不需要比您已有的代码更多的代码:
extension Dictionary
{
func someMethod()
{
for (key, value) in self
{
var valueRef = _reflect(value)
while valueRef.disposition == .Optional && valueRef.count > 0 && valueRef[0].0 == "Some"
{
valueRef = valueRef[0].1
}
if let valueString: String = valueRef.value as? String
{
print(" \(key) = \(valueString)")
}
else
{
print(" \(key) = \(value) cannot be cast to `String`")
}
}
}
}
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let dictionary: [String : AnyObject?] = ["foo" : "bar"]
dictionary.someMethod()
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退货
extension Dictionary
{
func someMethod()
{
for (key, value) in self
{
var valueRef = _reflect(value)
while valueRef.disposition == .Optional && valueRef.count > 0 && valueRef[0].0 == "Some"
{
valueRef = valueRef[0].1
}
if let valueString: String = valueRef.value as? String
{
print(" \(key) = \(valueString)")
}
else
{
print(" \(key) = \(value) cannot be cast to `String`")
}
}
}
}
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let dictionary: [String : AnyObject?] = ["foo" : nil]
dictionary.someMethod()
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退货
let dictionary: [String : AnyObject?] = ["foo" : "bar"]
dictionary.someMethod()
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let dictionary: [String : AnyObject?] = ["foo" : UIViewController()]
dictionary.someMethod()
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退货
foo = bar
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