Android:根据用户是否登录,更改活动启动我的应用程序？

Question

我必须像spotify一样开始,如果用户没有登录会显示一个屏幕,如果记录显示另一个屏幕,任何人都可以帮忙吗？,谢谢.

Answer 1

试试这段代码,它可能对你有所帮助.

public class SplashActivity extends Activity {
boolean isUserLoggedIn = true;
// User Session Manager Class
UserSessionManager session;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    session = new UserSessionManager(getApplicationContext());
    isUserLoggedIn = session.isUserLoggedIn();
    if(isUserLoggedIn)
    {
        Intent intent = new Intent(SplashActivity.this,FirstActivity.class);
        startActivity(intent);
        SplashActivity.this.finish();
    }
    else
    {
    setContentView(R.layout.splash_layout);
    Thread timer = new Thread(){
        public void run() {
            try
            {
                sleep(3000);
            }catch(InterruptedException e) { }
            finally
            {
                Intent intent = new Intent(SplashActivity.this,SecondActivity.class);
                startActivity(intent);
                SplashActivity.this.finish();
            }
        }
    };
    timer.start();
    }
}}

UserSessionManager类: -

public class UserSessionManager
{
public static final String KEY_EMAIL = "email";
public static final String KEY_NAME = "name";
int PRIVATE_MODE = 0;
Context _context;
SharedPreferences.Editor editor;
SharedPreferences pref;

public UserSessionManager(Context paramContext)
{
    this._context = paramContext;
    this.pref = this._context.getSharedPreferences("AndroidPref", this.PRIVATE_MODE);
    this.editor = this.pref.edit();
}

public void createUserLoginSession(String paramString1, String paramString2)
{
    this.editor.putBoolean("IsUserLoggedIn", true);
    this.editor.putString("name", paramString1);
    this.editor.putString("email", paramString2);
    this.editor.commit();
}

public HashMap<String, String> getUserDetails()
{
    HashMap<String, String> localHashMap = new HashMap<String, String>();
    localHashMap.put("name", this.pref.getString("name", null));
    localHashMap.put("email", this.pref.getString("email", null));
    return localHashMap;
}

public boolean isUserLoggedIn()
{
    return this.pref.getBoolean("IsUserLoggedIn", false);
}

public void logoutUser()
{

}}

您可以使用createUserLoginSession方法设置登录详细信息.

如果你不想使用飞溅等待.只需在SplashActivity类中删除setContentView方法和Thread.