除了代码中的url之外,我的脚本运行良好.我总是得到404.当然我可以从浏览器中获取图像.有人可以帮我解决这个问题吗?PS:实际上,我可以使用方法int"questions/6476212"来获取图像文件.但是在尝试打开图像文件时,文件中的内容是404页面而不是图像.
$url = 'https://spthumbnails.5min.com/10368406/518420256_c_570_411.jpg';
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_HEADER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.1 Safari/537.11');
$res = curl_exec($ch);
$rescode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch) ;
echo $res;"
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您的脚本已正确编写.我已经尝试并且工作正常,但您需要设置图像标题以便让导航器显示图像.
例:
header("Content-Type: image/jpeg");
$url = 'https://images.nga.gov/en/web_images/constable.jpg';
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_HEADER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.1 Safari/537.11');
$res = curl_exec($ch);
$rescode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch) ;
echo $res;
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但请注意您的图片网址已关闭,这就是您收到404错误的原因.
问候
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