比赛后的第一场比赛

Question

鉴于此文件,我想打印出该install:行之后的第一@ bash行.请参阅文件以获取完整输入,但这是一个示例

@ base-files
; few lines
install: x86_64/release/base-files/base-files-4.2-3.tar.xz 46428 6372358800e589b
; couple of lines
install: x86_64/release/base-files/base-files-4.1-1.tar.bz2 49519 f91ed6eab060c3

@ bash
; few lines
install: x86_64/release/bash/bash-4.1.17-9.tar.xz 1107128 e49b8d67d59d8617dfa31c
; couple of lines
install: x86_64/release/bash/bash-4.1.16-8.tar.xz 1106812 5aa652ddc0a5d65f4af1e2
source: x86_64/release/bash/bash-4.1.16-8-src.tar.xz 6614280 79bb3ddc67d8f0d3da6

@ bash-completion
; few lines
install: x86_64/release/bash-completion/bash-completion-1.3-1.tar.bz2 117489 538
source: x86_64/release/bash-completion/bash-completion-1.3-1-src.tar.bz2 216503

输出应该是

install: x86_64/release/bash/bash-4.1.17-9.tar.xz 1107128 e49b8d67d59d8617dfa...

我有这个命令,但它会打印包含这两个的所有行.

awk '/@ bash$/,/install:/' setup.ini

除了我创建这个答案的答案

awk '$1=="@" {c=$2} $1=="install:" && c=="bash" {print;exit}'

Answer 1

您可以使用:

awk '/@ bash$/{p=1} p&&/install:/{print; exit}' setup.ini
install: x86_64/release/bash/bash-4.1.17-9.tar.xz 1107128 e49b8d67d59d8617dfa31c