均匀地打印2个均匀填充的列表

Question

我正在使用以下代码生成2个列表,nameList和gradeList.

nameList[]        
gradeList[]
for row in soup.find_all('tr'):
        name = row.select('th strong')
        grade = row.select('td label')
        if grade and name:
            if "/" in grade[0].text:
                gradeList.append(grade[0].text)
                nameShort = re.sub(r'^(.{20}).*$', '\g<1>...', str(name[0].text))
                nameList.append(nameShort)

产生类似的东西:

nameList = [“grade 1”,”grade 2222222222”,”grade 3”]
gradeList = [“1/1”,”2/2”,”100000/100000”]

我希望程序能够并排打印2个清洁列中的列表.在每列中,我希望数据对齐到左侧.列表(没有失败)将始终均匀填充.第一列(nameList)永远不会超过25个字符.我正在寻找的将类似于以下内容:

        Assignment          Grade
0       grade 1             1/1
1       grade 2222222222    2/2
2       grade 3             100000/100000

我已经尝试过使用pandas并且它有效,但格式化很奇怪且不合适.它不会像我想的那样对齐左边.我相信这是因为每个数据在两个列表中都有不同的字符长度(如上所示).

Answer 1

使用str.format:

nameList = ["grade 1", "grade 2222222222", "grade 3"]
gradeList = ["1/1", "2/2", "100000/100000"]

fmt = '{:<8}{:<20}{}'

print(fmt.format('', 'Assignment', 'Grade'))
for i, (name, grade) in enumerate(zip(nameList, gradeList)):
    print(fmt.format(i, name, grade))

输出:

        Assignment          Grade
0       grade 1             1/1
1       grade 2222222222    2/2
2       grade 3             100000/100000

或者,您也可以printf使用%运算符使用样式格式:

fmt = '%-8s%-20s%s'

print(fmt % ('', 'Assignment', 'Grade'))
for i, (name, grade) in enumerate(zip(nameList, gradeList)):
    print(fmt % (i, name, grade))

Answer 2

鉴于两个清单

nameList = ['grade 1','grade 2222222222','grade 3']
gradeList = ['1/1','2/2','100000/100000']

制表符分隔格式.使用zip()两个同时迭代两个列表

print 'Assignment \t\tGrade' 
for n,g in zip(nameList,gradeList):
    print n + '\t\t\t' + g


Assignment         Grade
grade 1            1/1
grade 2222222222   2/2
grade 3            100000/100000