我有以下SQL SELECT语句
SELECT bar_id, bar_name, town_name, advert_text
FROM bar, towns, baradverts
WHERE town_id = town_id_fk
AND bar_id = bar_id_fk
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我的问题是,因为并非每个酒吧都有表格"baradverts"中的广告,所以结果中没有出现这些条形图.换句话说,对于那些没有广告字符串的栏,我需要一个NULL.
很难说哪个列与哪个表一起使用,但我认为这正是您要寻找的.如果您发布可能有用的架构.
SELECT bar_id, bar_name, town_name, advert_text
FROM bar b
inner join towns t on t.town_id = b.town_id_fk
left outer join baradverts ba on t.town_id = ba.town_id_fk
AND b.bar_id = ba.bar_id_fk
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