Javascript:如何以MM-DD-YYYY格式验证日期？

Question

我在这里看到了一个潜在的答案,但那是YYYY-MM-DD:JavaScript日期验证

我为MM-DD-YYYY修改了上面的代码,但我还是无法让它工作:

String.prototype.isValidDate = function() 
{
     var IsoDateRe = new RegExp("^([0-9]{2})-([0-9]{2})-([0-9]{4})$");
     var matches = IsoDateRe.exec(this);
     if (!matches) return false;
     var composedDate = new Date(matches[3], (matches[1] - 1), matches[2]);
     return ((composedDate.getMonth() == (matches[1] - 1)) &&
      (composedDate.getDate() == matches[2]) &&
      (composedDate.getFullYear() == matches[3]));
}

如何让上述代码适用于MM-DD-YYYY,更好的是MM/DD/YYYY？

谢谢.

Answer 1

function isValidDate(date)
{
    var matches = /^(\d{1,2})[-\/](\d{1,2})[-\/](\d{4})$/.exec(date);
    if (matches == null) return false;
    var d = matches[2];
    var m = matches[1] - 1;
    var y = matches[3];
    var composedDate = new Date(y, m, d);
    return composedDate.getDate() == d &&
            composedDate.getMonth() == m &&
            composedDate.getFullYear() == y;
}
console.log(isValidDate('10-12-1961'));
console.log(isValidDate('12/11/1961'));
console.log(isValidDate('02-11-1961'));
console.log(isValidDate('12/01/1961'));
console.log(isValidDate('13-11-1961'));
console.log(isValidDate('11-31-1961'));
console.log(isValidDate('11-31-1061'));

有用.(使用Firebug测试,因此使用console.log().)

Answer 2

function isValidDate(date) {
        var valid = true;

        date = date.replace('/-/g', '');

        var month = parseInt(date.substring(0, 2),10);
        var day   = parseInt(date.substring(2, 4),10);
        var year  = parseInt(date.substring(4, 8),10);

        if(isNaN(month) || isNaN(day) || isNaN(year)) return false;

        if((month < 1) || (month > 12)) valid = false;
        else if((day < 1) || (day > 31)) valid = false;
        else if(((month == 4) || (month == 6) || (month == 9) || (month == 11)) && (day > 30)) valid = false;
        else if((month == 2) && (((year % 400) == 0) || ((year % 4) == 0)) && ((year % 100) != 0) && (day > 29)) valid = false;
        else if((month == 2) && ((year % 100) == 0) && (day > 29)) valid = false;
        else if((month == 2) && (day > 28)) valid = false;

    return valid;
}

这将检查每个月的有效天数和有效的闰年天数.

Answer 3

如何以"任何"日期格式验证日期？我一直在使用DateJS库并将其添加到现有表单中,以确保我按照我想要的方式格式化有效的日期和时间.用户甚至可以输入"现在"和"明天"等内容,并将其转换为有效日期.

这是dateJS库:http://www.datejs.com/

这是我写的一个jQuery技巧:http: //www.ssmedia.com/utilities/jquery/index.cfm/datejs.htm

Answer 4

您可以通过将函数的前两行更改为以下内容来稍微简化它：

var matches = this.match(/^([0-9]{2})\/([0-9]{2})\/([0-9]{4})$/);

或者，只需将 RegExp 构造函数的参数更改为

^([0-9]{2})\/([0-9]{2})\/([0-9]{4})$