dze*_*siz 2 java string number-formatting numberformatexception
我遇到一个关于使用String输入和输出转换数字格式的类的问题:
public class Conversion{
static int result;
public static String fromHexToDec (String clientInput) {
result= Integer.parseInt(clientInput, 10);
return Integer.toString(result);
}
public static String fromDecToHex (String clientInput) {
result= Integer.parseInt(clientInput, 16);
return Integer.toString(result);
}
public static String fromOctTo4 (String clientInput) {
result= Integer.parseInt(clientInput, 4);
return Integer.toString(result);
}
public static String from4ToOct(String clientInput) {
result= Integer.parseInt(clientInput, 8);
return Integer.toString(result);
}
public static String formBinToDec(String clientInput) {
result= Integer.parseInt(clientInput, 10);
return Integer.toString(result);
}
public static String fromDecToBin(String clientInput) {
result= Integer.parseInt(clientInput, 2);
return Integer.toString(result);
}
public static String from5To7(String clientInput) {
result= Integer.parseInt(clientInput, 7);
return Integer.toString(result);
}
public static String from7To5(String clientInput) {
result= Integer.parseInt(clientInput, 5);
return Integer.toString(result);
}
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}
我收到此错误尝试在main方法中从HexToDec运行:
Exception in thread "main" java.lang.NumberFormatException: For input string: "C"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at Konverzija.fromHexToDec(Conversion.java:9)
at Test.main(Test.java:5)
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有人可以帮帮忙吗?
因为
public static String fromHexToDec (String clientInput) {
result= Integer.parseInt(clientInput, 10);
return Integer.toString(result);
}
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正在将基数传递10给parseInt()(并且在十进制中无效).使用16喜欢
public static String fromHexToDec (String clientInput) {
result= Integer.parseInt(clientInput, 16);
return Integer.toString(result);
}
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而且fromDecToHex大概应该是
public static String fromDecToHex(String clientInput) {
int result = Integer.parseInt(clientInput, 10);
return Integer.toString(result, 16);
}
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要么
public static String fromDecToHex(String clientInput) {
int result = Integer.parseInt(clientInput);
return String.format("%02X", result);
}
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第二个具有零填充的潜在优势.