Bjö*_*lex 0 sqlite select jdbc foreign-keys insert
我有两张桌子,Proteins
和Species
.Protein
有Species.Id
外键约束.当我插入数据时,我知道蛋白质所属物种的名称,但不知道Id
.所以我做了以下事情:
PreparedStatement query = connection.prepareStatement(
"SELECT Id FROM Species WHERE ShortName = ?");
query.setString(1, protein.getSpecies().getShortName());
ResultSet result = query.executeQuery();
if (result.next()) {
PreparedStatement statement = connection.prepareStatement(
"INSERT INTO Proteins(SpeciesId, UniProtKBAccessionNumber) VALUES (?, ?)");
statement.setString(1, result.getString(1));
statement.setString(2, protein.getUniProtKBAccessionNumber().toString());
statement.execute();
}
else
throw new IllegalArgumentException("The species of this protein is not recognized!");
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基本上,我得到与名称对应的Id,然后插入蛋白质.这在许多方面看起来非常笨拙.是否有更优雅的方式来实现这一目标?我正在研究SQLite数据库.
试试这个
INSERT INTO Proteins(SpeciesId, UniProtKBAccessionNumber) VALUES ((SELECT Id FROM Species WHERE ShortName = ?), ?)
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然后使用Shortname和UniProtKBAccessionNumber作为参数