在sonata-admin中从sidemenu中删除子管理员

jla*_*rte 2 php symfony symfony-sonata sonata-admin

我有一个EmployeeAdminsonata-admin,配置了三个子管理员:

sonata.admin.employee:
    class: Medicina\InasistenciasBundle\Admin\EmployeeAdmin
    tags:
        - { name: sonata.admin, manager_type: orm, group: "Contenido", label: "Empleados", label_translator_strategy: "sonata.admin.label.strategy.underscore" }
    arguments:
        - ~
        - Medicina\InasistenciasBundle\Entity\Employee
        - MedicinaInasistenciasBundle:EmployeeCRUD
    calls:
        - [ setTranslationDomain, [MedicinaInasistenciasBundle]]
        - [ addChild, [@sonata.admin.compensatory_part]]
        - [ addChild, [@sonata.admin.compensatory]]
        - [ addChild, [@sonata.admin.absence]]
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孩子的管理员几乎都是一样的,这里有一个:

 sonata.admin.compensatory_part:
    class: Medicina\InasistenciasBundle\Admin\CompensatoryPartAdmin
    tags:
        - { name: sonata.admin, manager_type: orm, group: "Contenido", label: "Módulos de Tiempo",label_translator_strategy: "sonata.admin.label.strategy.underscore" }
    arguments:
        - ~
        - Medicina\InasistenciasBundle\Entity\CompensatoryPart
        - MedicinaInasistenciasBundle:DeleteValidationCRUD
    calls:
        - [setTranslationDomain, [MedicinaInasistenciasBundle]]
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如何避免子模板出现在sonatas侧面菜单中?

奏鸣曲菜单的截图

我已经尝试删除标签标签,但随后奏鸣曲将它们粘贴在没有名称的"默认"组中.我确信这是微不足道的,但我似乎无法在文档中找到它.有任何想法吗?

sja*_*agr 8

show_in_dashboard: false标记添加到要从菜单中排除的管理服务.

tags:
    - { name: sonata.admin, manager_type: orm, group: "Contenido", label: "Módulos de Tiempo",label_translator_strategy: "sonata.admin.label.strategy.underscore", show_in_dashboard: false }
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保留grouplabel标记,以便它们在集合中正确显示并键入管理员!