如何解析xml到hashmap？

Question

我有一个我要解析的xml示例

 <?xml version="1.0" encoding="utf-8"?>

<Details>
    <detail-a>

        <detail> attribute 1 of detail a </detail>
        <detail> attribute 2 of detail a </detail>
        <detail> attribute 3 of detail a </detail>

    </detail-a>

    <detail-b>
        <detail> attribute 1 of detail b </detail>
        <detail> attribute 2 of detail b </detail>

    </detail-b>


</Details>

我想从这个xml编写一个方法,将它解析为hashmap,键是一个字符串,值是一个字符串列表.

例如:键"detail a"value = {"详细信息的属性1","详细信息的属性2","详细信息的属性3"}

等等..

做这个的最好方式是什么 ？因为我很困惑:

我到目前为止试图打印细节-a和细节-b但是我感到空白......

public static void main(String[] args) {
    // TODO Auto-generated method stub

    DocumentBuilderFactory factory=DocumentBuilderFactory.newInstance();

        DocumentBuilder builder;
        try {
            builder = factory.newDocumentBuilder();
            File f= new File("src/Details.xml");
            Document doc=builder.parse(f);
            Element root=doc.getDocumentElement();
            NodeList children=root.getChildNodes();
            for(int i=0;i<children.getLength();i++)
            {
                Node child=children.item(i);
                if (child instanceof Element)
                {
                    Element childElement=(Element) child;
                    Text textNode=(Text)childElement.getFirstChild();
                    String text=textNode.getData().trim();
                    System.out.println(text);

                }
            }

        } catch (ParserConfigurationException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();   
        } catch (SAXException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

Answer 1

Underscore-java库有一个静态方法 U.fromXmlMap(xmlstring)。实例

import com.github.underscore.U;
import java.util.Map;

public class Main {

  public static void main(String[] args) {

    Map<String, Object> map = U.fromXmlMap(
        "<Details>\r\n" + 
        "    <detail-a>\r\n" + 
        "\r\n" + 
        "        <detail> attribute 1 of detail a </detail>\r\n" + 
        "        <detail> attribute 2 of detail a </detail>\r\n" + 
        "        <detail> attribute 3 of detail a </detail>\r\n" + 
        "\r\n" + 
        "    </detail-a>\r\n" + 
        "\r\n" + 
        "    <detail-b>\r\n" + 
        "        <detail> attribute 1 of detail b </detail>\r\n" + 
        "        <detail> attribute 2 of detail b </detail>\r\n" + 
        "\r\n" + 
        "    </detail-b>\r\n" + 
        "\r\n" + 
        "\r\n" + 
        "</Details>");
    
    System.out.println(map);
    // {Details={detail-a={detail=[ attribute 1 of detail a ,  attribute 2 of detail a ,  attribute 3 of detail a ]},
    // detail-b={detail=[ attribute 1 of detail b ,  attribute 2 of detail b ]}}, #omit-xml-declaration=yes}
  }
}

Answer 2

用于JAXB读取xml并将其保存到自定义对象。

自定义对象类：

import java.util.List;

import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlElementWrapper;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;

@XmlRootElement(name = "Details")
@XmlType(propOrder = { "detailA", "detailB" })
public class Details {
    private List<String> detailA;
    private List<String> detailB;

    public void setDetailA(List<String> detailA) {
        this.detailA = detailA;
    }

    @XmlElementWrapper(name = "detail-a")
    @XmlElement(name = "detail")
    public List<String> getDetailA() {
        return detailA;
    }

    public void setDetailB(List<String> detailB) {
        this.detailB = detailB;
    }

    @XmlElementWrapper(name = "detail-b")
    @XmlElement(name = "detail")
    public List<String> getDetailB() {
        return detailB;
    }
}

将数据从 xml 提取到对象中，然后根据需要将内容添加到地图中：

public static void main(String[] args) throws JAXBException, FileNotFoundException {
    System.out.println("Output from our XML File: ");
    JAXBContext context = JAXBContext.newInstance(Details.class);
    Unmarshaller um = context.createUnmarshaller();
    Details details = (Details)um.unmarshal(new FileReader("details.xml"));
    List<String> detailA = details.getDetailA();
    List<String> detailB = details.getDetailB();

    Map<String, String[]> map = new HashMap<String, String[]>();
    map.put("detail-a", detailA.toArray(new String[detailA.size()]));
    map.put("detail-b", detailB.toArray(new String[detailB.size()]));


    for (Map.Entry<String, String[]> entry : map.entrySet()) {
        //key "detail a" value={"attribute 1 of detail a","attribute 2 of detail a","attribute 3 of detail a"}
        System.out.print("Key \"" +entry.getKey()+"\" value={");
        for(int i=0;i<entry.getValue().length;i++){
            if(i!=entry.getValue().length-1){
                System.out.print("\""+entry.getValue()[i]+"\",");
            }
            else{
                System.out.print("\""+entry.getValue()[i]+"\"}");
            }
        }
        System.out.println();
    }
}

输出将是：

XML 文件的输出：
键“detail-a”值={“详细信息a的属性1”，“详细信息a的属性2”，“详细信息a的属性3”}
键“detail-b”值={“详细信息 b 的属性 1”,“详细信息 b 的属性 2”}

请注意：这仅适用于您在问题中作为输入提供的 xml，如果您需要添加更多详细信息等，detail-c您也必须在自定义对象中定义它们。

使用的 XML：

<?xml version="1.0" encoding="utf-8"?>
<Details>
    <detail-a>
        <detail>attribute 1 of detail a</detail>
        <detail>attribute 2 of detail a</detail>
        <detail>attribute 3 of detail a</detail>
    </detail-a>
    <detail-b>
        <detail>attribute 1 of detail b</detail>
        <detail>attribute 2 of detail b</detail>
    </detail-b>
</Details>