Jay*_*Jay 4 python postgresql psycopg2
我有以下查询cur.execute("SELECT COUNT(addr) FROM list_table WHERE addr = '192.168.1.1'")来计算相同地址(192.168.1.1)出现在list_table表上的次数.addr属于inet类型.
当我将查询分配给变量并打印其结果时,我得到None:
res = cur.execute("SELECT COUNT(addr) FROM list_table WHERE addr = '192.168.1.1'")
print res # None
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得到这样的东西的正确方法是什么?
您可以使用以下步骤使用python检索关系数据库的数据:
#!/usr/bin/python
# import the desired package
import MySQLdb
# Open database connection
db = MySQLdb.connect(hostaddress,user,password,db_name)
# prepare a cursor object using cursor() method
cursor = db.cursor()
# execute SQL query using execute() method.
cursor.execute("SELECT COUNT(addr) FROM list_table WHERE addr = '192.168.1.1'")
# Fetch a single row using fetchone() method and store the result in a variable.
data = cursor.fetchone()
#OR use fetchall() method to fetch multiple rows and store the result in a list variable.
data = cursor.fetchall()
print data
# disconnect from server
db.close()
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小智 5
您必须使用fetchone()或fetchall()从游标中获取行。
看看可用的fetch方法。
就您而言,大致如下:
res = cur.execute("SELECT COUNT(addr) FROM list_table WHERE addr = '192.168.1.1'")
row = cur.fetchone()
print(row)
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