如何通过R中的附加因子变量为树形图的标签着色

Question

我使用下面的代码在R中运行层次聚类分析后生成了一个树形图.我现在尝试根据另一个因子变量为标签着色,该变量保存为矢量.我实现这一目标的最接近的方法是使用包中的ColourDendrogram函数对分支进行颜色编码sparcl.如果可能的话,我更愿意对标签进行颜色编码.我在以下链接中找到了类似问题的答案在树形图中使用现有列和着色分支的树形图的颜色分支,但是我还没有能够找到如何为我的目的转换示例代码.下面是一些示例数据和代码.

> dput(df)
structure(list(labs = c("a1", "a2", "a3", "a4", "a5", "a6", "a7", 
"a8", "b1", "b2", "b3", "b4", "b5", "b6", "b7"), var = c(1L, 
1L, 2L, 1L, 2L, 2L, 1L, 2L, 1L, 2L, 1L, 1L, 2L, 2L, 2L), td = c(13.1, 
14.5, 16.7, 12.9, 14.9, 15.6, 13.4, 15.3, 12.8, 14.5, 14.7, 13.1, 
14.9, 15.6, 14.6), fd = c(2L, 3L, 3L, 1L, 2L, 3L, 2L, 3L, 2L, 
4L, 2L, 1L, 4L, 3L, 3L)), .Names = c("labs", "var", "td", "fd"
), class = "data.frame", row.names = c(NA, -15L))

df.nw = df[,3:4]
labs = df$labs

d = dist(as.matrix(df.nw))                          # find distance matrix 
hc = hclust(d, method="complete")                   # apply hierarchical clustering 
plot(hc, hang=-0.01, cex=0.6, labels=labs, xlab="") # plot the dendrogram

hcd = as.dendrogram(hc)                             # convert hclust to dendrogram 
plot(hcd, cex=0.6)                                  # plot using dendrogram object

Var = df$var                                        # factor variable for colours
varCol = gsub("1","red",Var)                        # convert numbers to colours
varCol = gsub("2","blue",varCol)

# colour-code dendrogram branches by a factor 
library(sparcl)
ColorDendrogram(hc, y=varCol, branchlength=0.9, labels=labs,
                xlab="", ylab="", sub="")   

任何关于如何做到这一点的建议将不胜感激.

Answer 1

尝试

# ... your code
colLab <- function(n) {
  if(is.leaf(n)) {
    a <- attributes(n)
    attr(n, "label") <- labs[a$label]
    attr(n, "nodePar") <- c(a$nodePar, lab.col = varCol[a$label]) 
  }
  n
}
plot(dendrapply(hcd, colLab))

（通过）