skr*_*use 26 python windows keyboardinterrupt python-3.4 python-asyncio
我有一个非常小的测试程序,除了执行asyncio事件循环之外什么都不做:
import asyncio
asyncio.get_event_loop().run_forever()
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当我在Linux上运行此程序并按Ctrl+时C,程序将正常终止,但有KeyboardInterrupt异常.在Windows上按Ctrl+ C什么也没做(用Python 3.4.2测试).即使在Windows上,一个简单的无限循环也能正确time.sleep()引发KeyboardInterrupt:
import time
while True:
time.sleep(3600)
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为什么asyncio的事件循环会抑制Windows上的KeyboardInterrupt?
And*_*lov 19
肯定是这个错误.
请参阅python bug-tracker上的问题以解决问题.
far*_*ncz 14
Windows有解决方法.运行另一个corouting,每秒唤醒循环,并允许循环对键盘中断作出反应
来自asyncio doc的Echo服务器示例
async def wakeup():
while True:
await asyncio.sleep(1)
loop = asyncio.get_event_loop()
coro = loop.create_server(EchoServerClientProtocol, '127.0.0.1', 8888)
server = loop.run_until_complete(coro)
# add wakeup HACK
loop.create_task(wakeup())
try:
loop.run_forever()
except KeyboardInterrupt:
pass
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Bar*_*son 11
如果您只想退出程序而不需要捕获KeyboardInterrupt,则信号模块提供了一种更简单(更有效)的解决方法:
# This restores the default Ctrl+C signal handler, which just kills the process
import signal
signal.signal(signal.SIGINT, signal.SIG_DFL)
# Now the event loop is interruptable
import asyncio
asyncio.get_event_loop().run_forever()
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